O Macmillan LearningFor the reactionKCIO4KCl + 20₂assign oxidation numbers to each element on each side of the equation.K in KCIO4:Cl in KC104:O in KCIO4:Which element is oxidized?K in KCl:Cl in KCl:O in 0₂:Which element is reduced?

Here we have to determine the oxidation number of the atoms in the redox reaction.

For the reaction KCIO4 → KCI + 20₂ assign oxidation numbers to each element on each side of the equation. K in KClO4: Cl in KC104: O in KC104: Which element is oxidized? K in KCl: Cl in KC1: O in 0₂: Which element is reduced?

For the reaction KCIO4 → KCI + 20₂ assign oxidation numbers to each element on each side of the equation. K in KClO4: Cl in KC104: O in KC104: Which element is oxidized? K in KCl: Cl in KC1: O in 0₂: Which element is reduced?

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

O Macmillan Learning
For the reaction
KCIO4
KCl + 20₂
assign oxidation numbers to each element on each side of the equation.
K in KCIO
4:
Cl in KC104:
O in KCIO4:
Which element is oxidized?
K in KCl:
Cl in KCl:
O in 0₂:
Which element is reduced?

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