G.18.I need all parts ... For the reaction described below, K= 1.22x10-²2 ICI(g) 1₂(g) + Cl₂(9)Calculate the equilibrium concentration of 1, if [ICI] = 0.406 M.0.0466XMFor the reaction described below, K₂ = 6.20×10-¹0.HCN(aq) + H₂O(1) H30+ (aq) + CN¯(aq)Calculate the equilibrium concentration of CN and the pH if [HCN] = 0.395 M.[CN ] =pH = 9.42XIf you have 300. mL of a 0.524 M NaBr solution, what will the concentration be when 583 mL of water is added?0.270XM

For the first question, we have to find the equilibrium concentration of I2 if [ICl]0 is 0.406 M…

For the reaction described below, K 1.22x10-². 2 ICI(g) 1₂(9) + Cl₂(9) Calculate the equilibrium concentration of 12 if [ICI], 0.406 M. XM 0.0466 For the reaction described below, K₂ = 6.20×10-10. HCN(aq) + H₂O() = H30+ (aq) + CN (aq) Calculate the equilibrium concentration of CN and the pH if [HCN] = 0.395 M. [CN ] M pH = 9.42 x If you have 300. mL of a 0.524 M NaBr solution, what will the concentration be when 583 mL of water is added? 0.270 XM

For the reaction described below, K 1.22x10-². 2 ICI(g) 1₂(9) + Cl₂(9) Calculate the equilibrium concentration of 12 if [ICI], 0.406 M. XM 0.0466 For the reaction described below, K₂ = 6.20×10-10. HCN(aq) + H₂O() = H30+ (aq) + CN (aq) Calculate the equilibrium concentration of CN and the pH if [HCN] = 0.395 M. [CN ] M pH = 9.42 x If you have 300. mL of a 0.524 M NaBr solution, what will the concentration be when 583 mL of water is added? 0.270 XM

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Similar questions

6. 1.23 x 104 is equal to A. 0.0000123 B. 0.000123 C. 1.230000 D. 123000 E. 1230000
Types of volumetric analysis are. Three. Five. Four.
PERCENT SOLUTIONS Many chemical solutions are mixed as percent concentrations. When working with a dry chemical, the percent is calculated as grams dry chemical in 100 ml. This is known as a weight/volume or W/V formula. 0.9% (w/v) NaCl solution is ………. g NaCl in ………. ml water. When the formula includes a liquid chemical, then the percent solution is volume added chemical in ml made up to 100 ml with solvent. 10% (v/v) acetic acid solution in water is ………. ml glacial acetic acid added to ………. ml water.
a. 3. Brex b. Brzy Bra d. Brzy
Q8. Copper is well-known conductive material, but it can lose its conductivity if size is reduced to nanometres. This happens due to.... Your answer
15.It is accurate to use measuring device calibrated in the US system in measuring quantities directed in the English prescriptions?a.Trueb.False16.Specific gravity determination is important because ita.Allows calculation of weights of a given volume of liquidb.Measures purity and strength of substancesc.Serve to identify substancesd.All of these
2. Fill the blanks with the possible physical methods of separation/processes. Matter Heterogeneous Physical Methods Homogeneous mixture mixture а. b. С.
7. 112 liters (L) to cups (c.) %3D %3D 8. 0300 kilometers (Km) to inches (in.)
Can you explain further how you will know that aspartame will hve a smaller volume? Aren't both cans supposed to be the same size.You also said that mass will stay consistent but there is less apartame. Can you clarify this please?
Question 25 Choose the major organic product for the following reactions: 1) P-TaCI / pyridine HO, 0.03 M CH,CH20-Na* 35 °C In ELOH/DMSO 2)
3.A particular glassware chosen in any situation will depend primarily upon two factors. Which of these is not a factor?a.Stability of the liquidb.The required volumec.Accuracy for the measurement4.Volume of liquids is ordinarily measured using the following with the exception ofa.Pipetb.Evaporating dishc.Graduated cylinderd.Volumetric flask
I will give answer in some hour . . . . . . . .