For the reaction Ca(OH)2(s) + H2SO4(e) → CaSO4(s) + 2H2O(e) AH° = -94.3 kJ/mol %3D How many kJ of heat are liberated or absorbed when 39.32 g of Ca(OH)2 (74.0 g/mol) are reacted with 82.94 g of H2SO4 (98.08 g/mol)? Use correct sign. Enter a number in kJ to 1 decimal place.
For the reaction Ca(OH)2(s) + H2SO4(e) → CaSO4(s) + 2H2O(e) AH° = -94.3 kJ/mol %3D How many kJ of heat are liberated or absorbed when 39.32 g of Ca(OH)2 (74.0 g/mol) are reacted with 82.94 g of H2SO4 (98.08 g/mol)? Use correct sign. Enter a number in kJ to 1 decimal place.
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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Transcribed Image Text:For the reaction
Ca(OH)2(s) + H2SO4(e) → CaSO4(s) + 2H20(e) AH° = -94.3 kJ/mol
%3D
How many kJ of heat are liberated or absorbed when 39.32 g of Ca(OH), (74.0 g/mol) are reacted
with 82.94 g of H,SO4 (98.08 g/mol)? Use correct sign. Enter a number in kJ to 1 decimal place.
Expert Solution

Step 1
The reaction taking place is given as,
Given : Mass of Ca(OH)2 taken = 39.32 g
And mass of H2SO4 taken = 82.94 g
Since mass = moles X molar mass
=> 39.32 = moles of Ca(OH)2 taken X 74.0
=> Moles of Ca(OH)2 taken = 0.53135 mol approx.
And 82.94 = moles of H2SO4 taken X 98.08
=> Moles of H2SO4 taken = 0.8456 mol approx.
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