f 1.005 moles of nitric acid are completely neutralized by an equivalent number of moles of sodium hydroxide, what is the heat of reaction in kJ? attached is the equations needed

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If 1.005 moles of nitric acid are completely neutralized by an equivalent number of moles of sodium hydroxide, what is the heat of reaction in kJ?

attached is the equations needed

When one mole of sodium hydroxide reacts, 57.3 kJ of heat are released.

\[ \text{HNO}_3 + \text{NaOH} \rightarrow \text{NaNO}_3 + \text{H}_2\text{O} \quad \Delta H_{\text{rxn}} = -57.3 \, \text{kJ/mol} \]

The amount of reactants used is the molar equivalent to that given in the balanced equation.
Transcribed Image Text:When one mole of sodium hydroxide reacts, 57.3 kJ of heat are released. \[ \text{HNO}_3 + \text{NaOH} \rightarrow \text{NaNO}_3 + \text{H}_2\text{O} \quad \Delta H_{\text{rxn}} = -57.3 \, \text{kJ/mol} \] The amount of reactants used is the molar equivalent to that given in the balanced equation.
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