For the reaction:\[ \text{C}_2\text{N}_2(g) + 2\text{O}_2(g) \rightarrow 2\text{CO}_2(g) + \text{N}_2(g) \]\[\Delta S^\circ \] is equal to \(-32 \text{ J/K}\). Use this value and data from the table below to calculate the value of \( S^\circ \) for \( \text{C}_2\text{N}_2(g) \).\[\begin{array}{|c|c|}\hline\text{Substance and State} & S^\circ (\text{J/K} \cdot \text{mol}) \\\hline\text{O}_2(g) & 205 \\\text{CO}_2(g) & 214 \\\text{N}_2(g) & 192 \\\hline\end{array}\]\( S^\circ = \) \(\_\) J/K·molButtons below the table:- "Submit Answer"- "Try Another Version"10 item attempts remaining.

The entropy change of a reaction is given by ∆S° = ∑nS°(products) - ∑mS°(reactants)Thus, the entropy change for the given reaction is given by: ∆S° = 2mol×S°CO2(g) + 1mol×S°N2(g) - 1mol×S°C2N2 (g)+ 2mol×S°O2(g)-32 JK-1 = 2mol×214 JK-1mol-1 + 1mol×192JK-1mol-1- 1mol×S°C2N2 (g)+ 2mol×205JK-1mol-1-32 JK-1 = 428 JK-1 + 192JK-1 - 1mol×S°C2N2 (g) - 410 JK-11mol×S°C2N2 (g) = 242 JK-1S°C2N2 (g) = 242 JK-1mol-1 Hence, So for C2H2 (g) is 242 J/(K.mol)

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For the reaction C2N2 (9) + 202 (g) + 2CO2 (9) + N2 (g) AS° is equal to -32 J/K. Use this value and data from the table below to calculate the value of S° for C2N2(g). Substance S° (J/K · mol) and State 02 (9) CO2 (9) 205 214 N2 (g) 192

For the reaction C2N2 (9) + 202 (g) + 2CO2 (9) + N2 (g) AS° is equal to -32 J/K. Use this value and data from the table below to calculate the value of S° for C2N2(g). Substance S° (J/K · mol) and State 02 (9) CO2 (9) 205 214 N2 (g) 192

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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