For the reaction below: 1. Draw all reasonable elimination products to the right of the arrow. 2. In the box below the reaction, redraw any product you expect to be a major product. ㄖˋ + X $ Cl NaOH
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- Draw one product of an elimination reaction between the molecules below. Note: There may be several correct answers. You only need to draw one of them. You do not need to draw any of the side products of the reaction. o* o Br SH Ö + X Click and drag to start drawing a structure.Draw the major products of this organic reaction.Draw the least stable resonance form for the intermediate in the following electrophilic substitution reaction. CF3 CF3 Br2/FeBr3 • You do not have to consider stereochemistry. • Include all valence lone pairs in your answer. Br In cases where there is more than one answer, just draw one. Br F ?
- 1The mechanism proceeds through a first cationic intermediate, intermediate 1. Nucleophilic attack leads to intermediate 2, which goes on to form the final product. In cases that involve negatively charged nucleophile, the attack of the nucleophile leads directly to the product. H. Br + CH3OH Br Intermediate 2 (product) Intermediate 1 In a similar fashion, draw intermediate 1 and intermediate 2 (final product) for the following reaction. OCH3 Cl2 MEOH ĆI racemic mixture Pay attention to the reactants, they may differ from the examples. In some reactions, one part of the molecule acts as the nucleophile. • You do not have to consider stereochemistry. • Draw one structure per sketcher. Add additional sketchers using the drop-down menu in the bottom right corner. Separate intermediate 1 and intermediate 2 using the the dropdown menu. → symbol fromHO Cro3 H2S04 Edit Click on the drawing box above to activate the MarvinSketch drawing tool and then draw your answer to this question. If there is no reaction, then check the "no reaction" box below. no reaction
- (Don't use hand raiting please)Use the image below to answer the following three questions. Note: Subscripts are not shown in answer choices, ex: H2 should be H2, NH3 should be NH3. Product A Product B Product C a. The reagents that would selectively yield Product A are [Select] b. The reagents that would selectively yield Product B are [ Sclect] c. The reagents that would selectively yield Product C are [ Select]Br CH3OH + Br-Br H3CO The mechanism proceeds through a first cationic intermediate, intermediate 1. Nucleophilic attack leads to intermediate 2, which goes on to form the final product. In cases that involve a negatively charged nucleophile, the attack of the nucleophile leads directly to the product. +Br + CH3OH Br Intermediate 1 Intermediate 2 (product) In a similar fashion, draw intermediate 1 and intermediate 2 (final product) for the following reaction. OH + Br2 + HBr Br racemic mixture • Pay attention to the reactants, they may differ from the examples. In some reactions, one part of the molecule acts as the nucleophile. • You do not have to consider stereochemistry. • Draw one structure per sketcher. Add additional sketchers using the drop-down menu in the bottom right corner. Separate intermediate 1 and intermediate 2 using the → symbol from the dropdown menu.
- Draw one product of an elimination reaction between the molecules below. Note: There may be several correct answers. You only need to draw one of them. You do not need to draw any of the side products of the reaction. Cl + + OH Click and drag to start drawing a structure. +1. Attack the alkyl chloride with the stronger nucleophile. 2. Deprotonated to form the productUse the image below to answer the following three questions. Note: Subscripts are not shown in answer choices, ex: H2 should be H2, NH3 should be NH3. Product A Product B Product C a. The reagents that would selectively yield ProductA are [ Select] b. The reagents that would selectively yield Product B are [Select] c. The reagents that would selectively yield Product Care [Select]
