For the reaction 8 H, S(g) =8 H, (g) + S,(g) the equilibrium concentrations were found to be [H, S] = 0.250 M, [H,] = 0.420 M, and [S,] = 0.750 M. %3D %3D %3D What is the equilibrium constant for this reaction? K.

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For the reaction
8 H, S(g) = 8 H, (g) + S, (g)
the equilibrium concentrations were found to be [H, S] = 0.250 M, [H,] = 0.420 M, and [S] = 0.750 M.
%D
What is the equilibrium constant for this reaction?
%3D
Transcribed Image Text:For the reaction 8 H, S(g) = 8 H, (g) + S, (g) the equilibrium concentrations were found to be [H, S] = 0.250 M, [H,] = 0.420 M, and [S] = 0.750 M. %D What is the equilibrium constant for this reaction? %3D
Expert Solution
Introduction :

Equilibrium constant :

This is defined for  reaction which are present in equilibrium form and it can be calculated by dividing  concentration of the products which is raised to power of stoichiometric coefficients with  concentration of reactants which is again raised to power of stoichiometric coefficients.

It is denoted by  " Keq".

Also, Equilibrium constant helps in deciding whether reaction will be reactant favored or product favored .

Calculation :

The given reaction is :

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