For the reaction2SO2(g) + O2(g) ----> 2SO3(g)delta H° = -198 kJ and delta S° = -188 J/KThe equilibrium constant, K, would be greater than 1 at temperatures _______(above/below) __________ Kelvin.Select above or below in the first line and enter the temperature in the second line. Assume that delta H° and delta S° are constant.
For the reaction2SO2(g) + O2(g) ----> 2SO3(g)delta H° = -198 kJ and delta S° = -188 J/KThe equilibrium constant, K, would be greater than 1 at temperatures _______(above/below) __________ Kelvin.Select above or below in the first line and enter the temperature in the second line. Assume that delta H° and delta S° are constant.
Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter17: Chemcial Thermodynamics
Section: Chapter Questions
Problem 17.20QE: The equilibrium constant for a reaction decreases as temperature increases. Explain how this...
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Question
For the reaction
2SO2(g) + O2(g) ----> 2SO3(g)
delta H° = -198 kJ and delta S° = -188 J/K
The equilibrium constant, K, would be greater than 1 at temperatures _______(above/below) __________ Kelvin.
Select above or below in the first line and enter the temperature in the second line. Assume that delta H° and delta S° are constant.
Expert Solution
Step 1
The temperature above or below and the temperature in kelvin has to be written.
Step 2
The chemical reaction is
2SO2(g) + O2(g) ----> 2SO3(g)
Given values:
delta H° = -198 kJ
delta S° = -188 J/K
The formula to calculate the standard Gibbs free energy is
The formula to calculate the equilibrium constant is
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