For the reaction2SO2(g) + O2(g) ----> 2SO3(g)delta H° = -198 kJ and delta S° = -188 J/KThe equilibrium constant, K, would be greater than 1 at temperatures _______(above/below) __________ Kelvin.Select above or below in the first line and enter the temperature in the second line. Assume that delta H° and delta S° are constant.

Chemistry: Principles and Practice
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Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter17: Chemcial Thermodynamics
Section: Chapter Questions
Problem 17.20QE: The equilibrium constant for a reaction decreases as temperature increases. Explain how this...
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For the reaction

2SO2(g) + O2(g) ----> 2SO3(g)

delta H° = -198 kJ and delta S° = -188 J/K

The equilibrium constant, K, would be greater than 1 at temperatures _______(above/below) __________ Kelvin.

Select above or below in the first line and enter the temperature in the second line. Assume that delta H° and delta S° are constant.

Expert Solution
Step 1

The temperature above or below and the temperature in kelvin has to be written.

Step 2

The chemical reaction is

2SO2(g) + O2(g) ----> 2SO3(g)

Given values:

delta H° = -198 kJ

delta S° = -188 J/K

The formula to calculate the standard Gibbs free energy is

Chemistry homework question answer, step 2, image 1

The formula to calculate the equilibrium constant is

Chemistry homework question answer, step 2, image 2

 

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