1. Let Z[√2] = {s+t√2 | s,t € Z}. Show that Z[√2] is a subring of R and that 1 + √2 is a unit in Z[√2].
1. Let Z[√2] = {s+t√2 | s,t € Z}. Show that Z[√2] is a subring of R and that 1 + √2 is a unit in Z[√2].
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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![1. Let
Z[√2] = {s+ t√2 | s,t € Z}.
Show that Z[√2] is a subring of R and that 1 + √2 is a unit in Z[√2].](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd0a2eb85-71bc-41a8-8f67-a7e3c7209cc3%2Ffd17fa40-d1a5-4afa-932c-d8dd307c9777%2F85ouls5_processed.jpeg&w=3840&q=75)
Transcribed Image Text:1. Let
Z[√2] = {s+ t√2 | s,t € Z}.
Show that Z[√2] is a subring of R and that 1 + √2 is a unit in Z[√2].
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Follow-up Question
For the proof that 1 + sqrt(2) is a unit, if c is 1 and d is -1 does that not make (1+ sqrt(2))(c + dsqrt(2)) = -1 not 1. Does this not mak the solution incorrect?
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