For the position shown where @ =53°, point 4 on the sliding collar has a constant velocity of v-1.25 m/s in the direction shown. At this instant BD is horizontal and DE is vertical, a) Find the velocity of point D and angular velocity of link DE by using instantaneous center of zero velocity, b) Find the angular acceleration of link BD and DE. 00 mm 101 1Pomm

For the position shown where @ =53°, point 4 on the sliding collar has a constant velocity of v-1.25 m/s in the direction shown. At this instant BD is horizontal and DE is vertical, a) Find the velocity of point D and angular velocity of link DE by using instantaneous center of zero velocity, b) Find the angular acceleration of link BD and DE. 00 mm 101 1Pomm

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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I'm trying to understand this problem is there an easier way to solve other than the the solution I attached? That just doesn't look like a relative acceleration equation it is so complicated any help is so appreciated thanks.
A four-bar linkage is shown in the figure (the ground "link" OC is considered the fourth bar). If the angular velocity and angular acceleration of drive link OA are 6.1 rad/s and 6.6 rad/s² respectively, both counterclockwise, determine the angular accelerations of bars AB and BC for the instant represented. The angular accelerations are positive if counterclockwise, negative if clockwise. The answers are not 2.356 and 11.327.
answer question 2)b)
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THE HOLLOW TUBE( NEED NEAT HANDWRITTEN SOLUTION ONLY OTHERWISE DOWNVOTE).
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Subject: mechanical