I'm trying to understand this problem is there an easier way to solve other than the the solution I attached? That just doesn't look like a relative acceleration equation it is so complicated any help is so appreciated thanks. Apply the relative acceleration equation.Aß = ªд + WẠb × VB/A + WAB × (WAB × rbia) + 2wab × (Vrel)x'y'z' + (Arel)x'y'z' (XI)Substitute {-50.46i – 32.60j} m/s² for ab, 0 for aд, -αABk for @AB, {0.6j} m for rB/A, -a-WABK for WAB and{-5.196j} m/s for (Vrel)x'y'z' in Equation (XI).-50.46i - 32.60j =[ 0 + (−¤µßk) × (0.6j) + (−wabk) × (-wabk × 0.6j)[0.60]+2 (−wabk) × (−5.196j) + (Arel)x'y'z'Substitute 5 rad/s for @AB in Equation (XII).-50.461 - 32.60j ==[ 0 + (−¤abk) × (0.6j) + (−5k) × (−5k × 0.6j)+2 (−5k) × (-5.196j) + (arel)x'y'z'-= (0.6αaß − 51.96)i + [(Arel)x'y'z' − 15] j(XII)(XIII) The peg B fixed on the gear slides freely alongthe slot in the link AB. If the gear's center Omoves with the velocity and acceleration shown inthe figure, determine the angular velocity andangular acceleration of the link AB at this instant.a) using the relative motion analysis and thecontact conditions.150 mmVo = 3 m/sao =1.5 m/s²150 mmrB---600 mm

To Find : The angular velocity and angular acceleration of link AB. Given : The acceleration of…

Answered: The peg B fixed on the gear slides…

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA