For the population of people in the United States who are at least 18 years of age, approximately 61 percent votedin a recent election. A random sample of 200 people and a random sample of 100 people will be selected from thepopulation.For which sample size is it more likely that greater than 70 percent of the sample voted in the recent election?(A) They are equally likely, because the mean of the sampling distribution is the same for both sample sizes.It is more likely for a sample size of 200 people, because there is more variability in the samplingdistribution for larger sample sizes.(B)(D)It is more likely for a sample size of 200 people, because there is less variability in the sampling distributionfor larger sample sizes.It is more likely for a sample of size 100 people, because there is more variability in the samplingdistribution for smaller sample sizes.It is more likely for a sample size of 100 people, because there is less variability in the sampling distributionfor smaller sample sizes.

The objective of the question is to determine for which sample size it is more likely that greater…

Answered: For the population of people in the…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Please give an answer with a calculation and give an explanation of the correct and incorrect option.
An amusement park keeps track of the percentage of individuals with season passes according to age category. An independent tourist company would like to show that this distribution of age category for individuals buying season passes is different from what the amusement park claims. The tourist company randomly sampled 200 individuals entering the park with a season pass and recorded the number of individuals within each age category. Age Category Child (under 13 years old) Teen (13 to 19 years old) Adult (20 to 55 years old) Senior (56 years old and over) Number of Individuals 56 86 44 14 The tourist company will use the data to test the amusement park’s claim, which is reflected in the following null hypothesis. H0:pchild=0.23H0:pchild=0.23, pteen=0.45pteen=0.45, padult=0.20padult=0.20, and psenior=0.12psenior=0.12. What inference procedure will the company use to investigate whether or not the distribution of age category for individuals with season passes is…
When two births are randomly selected, the sample space for genders is bb, bg, gb, and gg. Assume that those four outcomes are equally likely. Construct a table that describes the sampling distribution of the sample proportion of girls from two births. Does the mean of the sample proportions equal the proportion of girls in two births? Does the result suggest that a sample proportion is an unbiased estimator of a 1 1 population proportion? For the entire population, assume the probability of having a boy is the probability of having a girl is, and this is not affected by how many boys or girls have previously been born. Determine the probabilities of each sample proportion. Sample proportion of girls ▼ ▼ ▼ Probability (Type integers or simplified fractions.)
A sports magazine reports that the mean number of hot dogs sold by hot dog vendors at a certain sporting event is equal to 150. A random sample of 50 hot dog vendors was selected, and the mean number of hot dogs sold by the vendors at the sporting event was 140. For samples of size 50, which of the following is true about the sampling distribution of the sample mean number of hot dogs sold by hot dog vendors at the sporting event? For all random samples of 50 sporting events, the sample mean will be 150 hot dogs. A For all random samples of 50 hot dog vendors, the sample mean will be 140 hot dogs. B The mean of the sampling distribution of the sample mean is 150 hot dogs. C The mean of the sampling distribution of the sample mean is 140 hot dogs. D All random samples of 50 hot dog vendors will have a sample mean within 10 hot dogs of the population mean. E Chose A, B, C, D, or E
(c) Calculate the test statistic. d) Decide whether to reject or fail to reject the null hypothesis. Then interpret the decision in the context of the original claim.
A recent Gallup Poll interviewed a random sample of 1523 adults. Of these, 868 bought a lottery tickets in the past year. Suppose that in fact (unknown to Gallup) exactly 60% of all adults bought a lottery ticket in the past year. If Gallup took many simple random samples of 1,523 people, the sample proportion who bought a ticket would vary from sample to sample. The sampling distribution would be close to normal with a mean of 0.6 and a standard deviation of___ A)0.4899 B)0.0251 C)0.00016 D)0.0126
Does it seem to you that people tend to be absent more on some days of the week than on others? Recently, a major biotechnology firm collected data with the hope of determining whether or not its employees were more likely to be absent on some weekdays than on others. The firm examined a random sample of 130 employee absences. The distribution of these 130 absences is shown in the table below. The observed frequency for each category (each weekday) is shown in the first row of numbers. The second row of numbers contains the frequencies expected for a sample of 130 employees if employee absences at the firm are equally likely on each of the five weekdays. The bottom row of numbers contains the following value for each of the categories.
Suppose a random sample of 800 athletes from the college are asked what their major is. The table below shows the results of the survey. Observed Frequencies of Majors from the Sample Observed Frequency Outcome Math/Science 256 Arts & Humanities 190 Business & Economics 153 Other 201 The distribution of majors at the college is shown in the second column of the table below. Fill in the expected frequencies. (Round to the nearest whole number). Frequencies of Majors at the College Expected Percent Outcome Expected Frequency Math/Science 18 Arts & Humanities 29 Business & Economics 25
One cable company claims that it has excellent customer service. In fact, the company advertises that a technician will arrive within 45 minutes after a service call is placed. One frustrated customer believes this is not accurate, claiming that it takes over 45 minutes for the cable technician to arrive. The customer asks a simple random sample of 25 other cable customers how long it has taken for the cable technician to arrive when they have called for one. The sample mean for this group is 47.9 minutes with a standard deviation of 7.6 minutes. Assume that the population distribution is approximately normal. Test the customer's claim at the 0.01 level of significance. Step 1 of 3: State the null and alternative hypotheses for the test. Fill in the blank below. Ho : μ = 45 Ha:μ 45
At a large university, 68% of the students have a laptop, while only 43% of professors have one. Let and be the sample proportions of students and professors, respectively, who have a laptop. Suppose 56 students and 31 professors from this university are selected at random and asked if they have a laptop. Which of the following is the correct calculation and interpretation of the standard deviation of the sampling distribution of ? The difference (student – professor) in the sample proportions of those who have a laptop typically varies about 0.012 from the true difference in proportions. The difference (student – professor) in the sample proportions of those who have a laptop typically varies about 0.035 from the true difference in proportions. The difference (student – professor) in the sample proportions of those who have a laptop typically varies about 0.109 from the true difference in proportions. The difference (student – professor) in the sample proportions of those who…
(6) A student surveys some students on campus in the evening and finds that 16 out of 20 of the students she interviewed are part time students. She uses the data to estimate the percentage of all students who are part time. What type of bias is present in her sample?

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