For the nucleus 160 the neutron and proton se 12.2 MeV, respectively. Estimate the radius of particles are removed from its surface and tha energies is due to the Coulomb potential energy
For the nucleus 160 the neutron and proton se 12.2 MeV, respectively. Estimate the radius of particles are removed from its surface and tha energies is due to the Coulomb potential energy
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![For the nucleus ¹60 the neutron and proton separation energies are 15.7 and
12.2 MeV, respectively. Estimate the radius of this nucleus assuming that the
particles are removed from its surface and that the difference in separation
energies is due to the Coulomb potential energy of the proton.
[University of Wales, Aberystwyth 2004]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F87ec3034-dfc9-4ae1-9ad3-624d036387e3%2Fa5a7028d-2609-435a-a947-ec22236ae5fb%2Fm0epdf_processed.jpeg&w=3840&q=75)
Transcribed Image Text:For the nucleus ¹60 the neutron and proton separation energies are 15.7 and
12.2 MeV, respectively. Estimate the radius of this nucleus assuming that the
particles are removed from its surface and that the difference in separation
energies is due to the Coulomb potential energy of the proton.
[University of Wales, Aberystwyth 2004]
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