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For the network shown below (all values are in pu): 1+j0.75( j1.25 j0.8 a. j0.2 b. -j0.2 c. j5 j0.4 j0.2 j0.4 Having the nodal-admittance equation as follow: 1. The injected current into node 4 (14) is: a. j2.45 b. -j2.45 c. 1/(j2.45) d. -j4.55 j0.8 a. 1.5-j2 b. -2.5-j1.875 c. j2-1.5 d. 2.5+j1.875 2. The admittance entry in the Ybus (Y21) is: d. -j5 3. The admittance entry in the Ybus (Y33) is: 1.5-j2

For the network shown below (all values are in pu): 1+j0.75( j1.25 j0.8 a. j0.2 b. -j0.2 c. j5 j0.4 j0.2 j0.4 Having the nodal-admittance equation as follow: 1. The injected current into node 4 (14) is: a. j2.45 b. -j2.45 c. 1/(j2.45) d. -j4.55 j0.8 a. 1.5-j2 b. -2.5-j1.875 c. j2-1.5 d. 2.5+j1.875 2. The admittance entry in the Ybus (Y21) is: d. -j5 3. The admittance entry in the Ybus (Y33) is: 1.5-j2

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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For the network shown below (all values are in pu): 1+j0.75( j1.25 j0.8 a. j0.2 b. -j0.2 c. j5 j0.4 j0.2 j0.4 Having the nodal-admittance equation as follow: 1. The injected current into node 4 (14) is: a.j2.45 b. -j2.45 c. 1/(j2.45) d. -j4.55 j0.8 a. 1.5-j2 b. -2.5-j1.875 c. j2-1.5 d. 2.5+j1.875 2. The admittance entry in the Ybus (Y21) is: d. -j5 3. The admittance entry in the Ybus (Y33) is: 1.5-j2
Transcribed Image Text:For the network shown below (all values are in pu): 1+j0.75( j1.25 j0.8 a. j0.2 b. -j0.2 c. j5 j0.4 j0.2 j0.4 Having the nodal-admittance equation as follow: 1. The injected current into node 4 (14) is: a.j2.45 b. -j2.45 c. 1/(j2.45) d. -j4.55 j0.8 a. 1.5-j2 b. -2.5-j1.875 c. j2-1.5 d. 2.5+j1.875 2. The admittance entry in the Ybus (Y21) is: d. -j5 3. The admittance entry in the Ybus (Y33) is: 1.5-j2
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