For the network below, calculate a source current and currents through Rs and R6 and voltages on R4 and R7. R1=4k92 www R6=12k92 ww 16 Is R2= R4= E=72V V4 R1 8ΚΩ 24ΚΩ w R3=12k 15 w R5=12k R7=9kQ w 5 w R9=6k92 R8=3k2 ww Is I5 I6 V₁ V₁ Answers

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Current Division Method

The generalized current divider formula is given by the following relation below,