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For the loaded truss shown in Fig. 2 Calculate the internal axial force in the following members CF, DE and DF. 6 m 5 m 10 KN A 8.25 KN Oa. FDF=0 KN Ob. FCF= -20.2 KN Oc. FCF=-23.75 KN Od. FDF= 10 KN Oe. FDE44.375 KN- Ot. FDE 40.425 KN - O& FCF -18.2 KN Oh. FDF=2.5 KN OL FCF=-22.25 KN O FDE 42.375 KN Ok FDE 47.375 KN- OL FDF- 12.5 KN H B 5 m 5m 15 kN G Figure 2 15 KN F 5 m D E 21.75 KN 10 KN

For the loaded truss shown in Fig. 2 Calculate the internal axial force in the following members CF, DE and DF. 6 m 5 m 10 KN A 8.25 KN Oa. FDF=0 KN Ob. FCF= -20.2 KN Oc. FCF=-23.75 KN Od. FDF= 10 KN Oe. FDE44.375 KN- Ot. FDE 40.425 KN - O& FCF -18.2 KN Oh. FDF=2.5 KN OL FCF=-22.25 KN O FDE 42.375 KN Ok FDE 47.375 KN- OL FDF- 12.5 KN H B 5 m 5m 15 kN G Figure 2 15 KN F 5 m D E 21.75 KN 10 KN

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Question
For the loaded truss shown in Fig. 2 Calculate the internal axial force in the following members CF, DE and DF. 6 m 5 m 10 KN A 8.25 KN Oa. FDF=0 KN Ob. FCF -20.2 KN Oc. FCF=-23.75 KN Od. FDF= 10 KN Oe. FDE44.375 KN- Or. FDE40.425 KN - Og FCF -18.2 KN Oh. FDF=2.5 KN OL FCF-22.25 KN O FDE 42.375 KN Ok FDE47.375 KN- OL FDF- 12.5 KN H B 5 m 5m 15 KN G Figure 2 15 KN F 5 m D E 21.75 KN 10 KN
Transcribed Image Text:For the loaded truss shown in Fig. 2 Calculate the internal axial force in the following members CF, DE and DF. 6 m 5 m 10 KN A 8.25 KN Oa. FDF=0 KN Ob. FCF -20.2 KN Oc. FCF=-23.75 KN Od. FDF= 10 KN Oe. FDE44.375 KN- Or. FDE40.425 KN - Og FCF -18.2 KN Oh. FDF=2.5 KN OL FCF-22.25 KN O FDE 42.375 KN Ok FDE47.375 KN- OL FDF- 12.5 KN H B 5 m 5m 15 KN G Figure 2 15 KN F 5 m D E 21.75 KN 10 KN
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