3 kN VB 16 KN C VD | 1 KN VF |E 1.26 m-1.26 m-1.26 m- 1.26m → 1.2 m G 2. Determine the force in each member of the half hip truss shown. State whether each member is in tension of compression. Reaction at G is a roller support. (Ans: FAB = 5.80 KN (C), FAC = 4.20 KN (T), FBC = 0 KN, FCE = 4.20 KN (T), FBE = 1.450 kN (T), FBD = 5.25 KN (C), FDE = 6 KN (C), FDF = 5.25 KN (C), FEF = 7.25 KN (T), FEG = 0 KN, FFG = 6 KN (C)) SHOW ALL THE FBD AND FORCES GIVEN. DONT FORGET THE SYMBOLS COMPLETE WORK FOR UPVOTE
3 kN VB 16 KN C VD | 1 KN VF |E 1.26 m-1.26 m-1.26 m- 1.26m → 1.2 m G 2. Determine the force in each member of the half hip truss shown. State whether each member is in tension of compression. Reaction at G is a roller support. (Ans: FAB = 5.80 KN (C), FAC = 4.20 KN (T), FBC = 0 KN, FCE = 4.20 KN (T), FBE = 1.450 kN (T), FBD = 5.25 KN (C), FDE = 6 KN (C), FDF = 5.25 KN (C), FEF = 7.25 KN (T), FEG = 0 KN, FFG = 6 KN (C)) SHOW ALL THE FBD AND FORCES GIVEN. DONT FORGET THE SYMBOLS COMPLETE WORK FOR UPVOTE
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
Related questions
Question
100%
![АО
3 KN
VB
C
-1.26 m--1.26 m-
6 KN
VD
E
1.26 m-
1 kN
/F
T
1.2 m
G
2. Determine the force in each member of the half
hip truss shown. State whether each member is in
tension of compression. Reaction at G is a roller
support. (Ans: FAB = 5.80 KN (C), FAC = 4.20 KN (T),
FBC = 0 KN, FCE = 4.20 KN (T), FBE = 1.450 kN (T),
FBD = 5.25 KN (C), FDE = 6 KN (C), FDF = 5.25 kN (C),
FEF = 7.25 KN (T), FEG = 0 KN, FFG = 6 KN (C))
SHOW ALL THE FBD AND FORCES
GIVEN.
DONT FORGET THE SYMBOLS
COMPLETE WORK FOR UPVOTE](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7fc70597-7de9-4d95-bb98-47fe79963ee6%2Ff1998721-50c7-4fb9-8905-97a0e6b206cd%2Foddzfw_processed.jpeg&w=3840&q=75)
Transcribed Image Text:АО
3 KN
VB
C
-1.26 m--1.26 m-
6 KN
VD
E
1.26 m-
1 kN
/F
T
1.2 m
G
2. Determine the force in each member of the half
hip truss shown. State whether each member is in
tension of compression. Reaction at G is a roller
support. (Ans: FAB = 5.80 KN (C), FAC = 4.20 KN (T),
FBC = 0 KN, FCE = 4.20 KN (T), FBE = 1.450 kN (T),
FBD = 5.25 KN (C), FDE = 6 KN (C), FDF = 5.25 kN (C),
FEF = 7.25 KN (T), FEG = 0 KN, FFG = 6 KN (C))
SHOW ALL THE FBD AND FORCES
GIVEN.
DONT FORGET THE SYMBOLS
COMPLETE WORK FOR UPVOTE
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