For the list [44, 18, 74, 61, 42, 31], how will the array elements look like after second pass (after i-2 but before i=3) of the Insertion sort algorithm? def insertionSort(a): for i in range(1,len(a)): currentvalue = a[i] position = i while position>0 and a[position-1]>currentvalue: a[position]=a[position-1] position = position-1 a[position]=currentvalue return a [18, 44, 74, 61, 42, 31] [18, 44, 61, 74, 42, 31] [18, 42, 44, 61, 74, 31] [18, 31, 42, 44, 61, 74]
For the list [44, 18, 74, 61, 42, 31], how will the array elements look like after second pass (after i-2 but before i=3) of the Insertion sort algorithm? def insertionSort(a): for i in range(1,len(a)): currentvalue = a[i] position = i while position>0 and a[position-1]>currentvalue: a[position]=a[position-1] position = position-1 a[position]=currentvalue return a [18, 44, 74, 61, 42, 31] [18, 44, 61, 74, 42, 31] [18, 42, 44, 61, 74, 31] [18, 31, 42, 44, 61, 74]
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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![For the list [44, 18, 74, 61, 42, 31], how will the array elements look like after second
pass (after i-2 but before i=3) of the Insertion sort algorithm?
def insertionSort(a):
for i in range(1,len(a)):
currentvalue = a[i]
position = i
while position>0 and a[position-1]>currentvalue:
a[position]=a[position-1]
position = position-1
a[position]=currentvalue
return a
[18, 44, 74, 61, 42, 31]
[18, 44, 61, 74, 42, 31]
[18, 42, 44, 61, 74, 31]
[18, 31, 42, 44, 61, 74]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fcdba5689-bc14-44c2-a025-6db7a798c6e6%2Fd4667e93-dc4f-4e0e-8fe5-c96b0837ecdc%2F7t9e4tb_processed.png&w=3840&q=75)
Transcribed Image Text:For the list [44, 18, 74, 61, 42, 31], how will the array elements look like after second
pass (after i-2 but before i=3) of the Insertion sort algorithm?
def insertionSort(a):
for i in range(1,len(a)):
currentvalue = a[i]
position = i
while position>0 and a[position-1]>currentvalue:
a[position]=a[position-1]
position = position-1
a[position]=currentvalue
return a
[18, 44, 74, 61, 42, 31]
[18, 44, 61, 74, 42, 31]
[18, 42, 44, 61, 74, 31]
[18, 31, 42, 44, 61, 74]
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