For the given P-value, refer to the table to determine the strength of theevidence against the null hypothesis.P = 0.008The P-value givesP-valueP>0.100.05

Answer Given P-value Evidence against H0 P>0.10 Weak or none…

Answered: For the given P-value, refer to the…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Out of 300 people sampled, 150 voted in the last election. Based on this, construct a 99% confidence interval for the true population proportion of people who voted in the last election.Give your answers as decimals, to three places ______< p < ________
Express the confidence interval (34.3 % , 43.3 % ) in the form of p + ME. % Question Help: Message instructor Submit Question Previous DII 80 888 F6 F7 F8 F1 F2 F3 F4 F5 @ #3 $ & 3 4 7 8. Q W T Y S D G H J * 00 Al
Need the H0 and H1 values. Can use != for not equal to.
State whether the standardized test statistic t indicates that you should reject the null hypothesis. Explain. (a) t = -2.272 (b) t = 2.154 (c) t = 2.303 (d) t= -2.301 -to = -2.226 to = 2.226
B. Calculate the value of the test statistic. χ2=____ C. Use technology to determine the P-value for the test statistic. The P-value is______ D. What is the correct conclusion at the α=0.10 level of significance? Since the P-value is(greater or less)than the level of significance. (Do not reject or reject) the null hypothesis. There (is or is not) sufficient evidence to conclude that the standard deviation of heights of major-league baseball players is less than 2.4 inches at the 0.10 level of significance.
A hypothesis test is performed at the 5% significance for a normal population mean u iwth the null and alternative hypotheses given below. Haitl# Ho Orl =r1:0H It is found that the p-value is p = 0.0123. What is the correct decision and interpretation of the hypothesis test? O Inconclusive or not enough information to tell. O Do not reject the null hypothesis. Our data supports the null hypothesis. O Do not reject the null hypothesis. We have proved the null hypothesis is true. O Reject the null hypothesis. We have proved the null hypothesis is false. O Reject the null hypothesis. Our data is statistically insignificant. O Reject the null hypothesis. Our data does not support the null hypothesis.
Which confidence interval would lead you to Fail to Reject H0? Group of answer choices Test value: 10 Confidence Interval: 13.1 – 15.1 Test value: 5 Confidence Interval: 5.6 – 6.9 Test value: 5 Confidence Interval: 4.5 – 6.3 Test value: 10 Confidence Interval: 9.2 – 9.8
We wish to estimate what percent of adult residents in a certain county are parents. Out of 200 adult residents sampled, 188 had kids. Based on this, construct a 90% confidence interval for the proportion p of adult residents who are parents in this county.Express your answer in tri-inequality form. Give your answers as decimals, to three places._____ < p < _____ Express the same answer using the point estimate and margin of error. Give your answers as decimals, to three places.p = _____ ± _____
The test statistic in a right-tailed test is z=−1.83. Determine the P-value and decide whether, at the 5% significance level, the data provide sufficient evidence to reject the null hypothesis in favor of the alternative hypothesis. The P-value is _____________ (Round to three decimal places as needed.) This P-value _____________________ (does not provide or provides) sufficient evidence to reject the null hypothesis in favor of the alternative hypothesis because it is_____________ (greater than or less than) the significance level.
The graph portrays the decision criterion for a one-mean z-test. The curve in the graph is the normal curve for the test statistic under the assumption that the null hypothesis is true. Use the graph to solve the problem. A graphical display of the decision criterion follows. Reject Ho Reject Ho Do not reject Ho N 0.01 0.01 0 1 2 -3 -2 -1 -2.33 2.33 Determine the rejection region. OA. Z≥ 0.01 B. z -2.33 or z= 2.33 O C. z≤ -2.33 or z ≥ 2.33 O D. - 2.33 ≤z≤ 2.33
State whether the standardized test statistic t indicates that you should reject the null hypothesis. Explain. (a) t= 1.584 (b) t=0 (c) t= - 1.526 (d) t= - 1.604 to = - 1.558 (a) For t= 1.584, should you reject or fail to reject the null hypothesis? O A. Fail to reject Ho, because t> - 1.558. O B. Reject Ho, because t> - 1.558. O C. Reject Ho, because t - 1.558. O B. Fail to reject Ho, because t - 1.558. (c) For t= - 1.526, should you reject or fail to reject the null hypothesis? O A. Reject Ho, because t - 1.558. O C. Fail to reject Ho, because t> - 1.558. O D. Fail to reject Hn, because t< - 1.558.
Claim: The mean systolic blood pressure of all healthy adults is less than than 125 mm Hg. Sample data: For 266 healthy adults, the mean systolic blood pressure level is 124.47 mm Hg and the standard deviation is 15.29 mm Hg. The null and alternative hypotheses are Ho: μ = 125 and H₁: µ< 125. Find the value of the test statistic. C The value of the test statistic is. Round to two decimal places as needed.) ple Get more help - A X Question 6 (0/1) ✓ Question 10 (1/1) Question 7 (0.67/1) 4 Clear all Check answe Question 8 (0.67/1)

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For the given P-value, refer to the table to determine the strength of the evidence against the null hypothesis. P=0.008 The P-value gives ... P-value P>0.10 0.05