For the gas phase isomerization of methyl cis-cinnamate, the reaction is represented as follows:\[ \text{cis-C}_6\text{H}_5\text{CH=CHCOOCH}_3 \rightarrow \text{trans-C}_6\text{H}_5\text{CH=CHCOOCH}_3 \]The rate constant at 669 K is $9.12 \times 10^{-4} \, \text{s}^{-1}$, and the rate constant at 711 K is $5.79 \times 10^{-3} \, \text{s}^{-1}$.The activation energy for the gas phase isomerization of methyl cis-cinnamate is $\boxed{\phantom{00}}$ kJ.

The rate constant at Temperature 669 K, = The rate constant at Temperature 711 K, = Activation…

Answered: For the gas phase isomerization of…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

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For the gas phase isomerization of methyl cis-cinnamate, the reaction is represented as follows:

\[ \text{cis-C}_6\text{H}_5\text{CH=CHCOOCH}_3 \rightarrow \text{trans-C}_6\text{H}_5\text{CH=CHCOOCH}_3 \]

The rate constant at 669 K is $9.12 \times 10^{-4} \, \text{s}^{-1}$, and the rate constant at 711 K is $5.79 \times 10^{-3} \, \text{s}^{-1}$.

The activation energy for the gas phase isomerization of methyl cis-cinnamate is $\boxed{\phantom{00}}$ kJ.

Expert Solution

Step 1: Consider the given information:

The rate constant at Temperature 669 K, $open parentheses straight k subscript 1 close parentheses$ = $9.12 cross times 10 to the power of negative 4 end exponent space straight s to the power of negative 1 end exponent$

The rate constant at Temperature 711 K, $open parentheses straight k subscript 2 close parentheses$ = $5.79 cross times 10 to the power of negative 3 end exponent space space straight s to the power of negative 1 end exponent$

Activation energy $open parentheses straight E subscript straight a close parentheses$ = ?

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