For the galvanic (voltaic) cell Fe(s) +Mn2* (aq) →V at 25°C), what is [Fe2*] if [Mn²*] = 0.075M and E = 0.78 V? Assume T is 298 KFe2* (aq) + Mn(s) (E° = 0.77%3D%3Dtv

We can use the Nernst equation to calculate the Ecell of a reaction. We have to get number of…

For the galvanic (voltaic) cell Fe(s) + Mn2" (aq) Fe2*(aq) + Mn(s) (E° = 0.77 V at 25°C), what is [Fe2"] if [Mn²*] = 0.075 M and E = 0.78 V? Assume T is 298 K -> %3D %3D %3D

For the galvanic (voltaic) cell Fe(s) + Mn2" (aq) Fe2(aq) + Mn(s) (E° = 0.77 V at 25°C), what is [Fe2"] if [Mn²] = 0.075 M and E = 0.78 V? Assume T is 298 K -> %3D %3D %3D

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Related questions

Q: Calculate the standard e.m.f, standard free energy change and equilibrium constant for the following…

A: Answer: Since, Copper is getting oxidized therefore it will be at anode and chlorine is getting…

Q: For the galvanic (voltaic) cell: Zn(s) + 2TI*(aq)→ 2TI(s) + Zn2* (aq) E cell = 0.42 V If the…

Q: Consider the following cell. Cr | Cr³+ (1.00 M) || Ni²+(1.00 M) | Ni = 0.68 V (a) How many…

A: (b) Write the balanced chemical equation for the overall cell reaction and use the ICE table.

Q: What is K for the reaction Zn(s) + Cu²*(aq) ® Zn²*(aq) + Cu(s), given E°cell is 1.1 V at 25 °C for…

Q: 6) A galvanic cell is composed of these two half-cells, with the standard reduction potentials…

A: It is based on the concept of electrochemistry. Here we are required to find the standard Gibbs…

Q: The nickel-cadmium rechargeable cell follows this overall reaction: Cds) + NiO2(s) + 2H2O + 2OH- ⇌…

A: The objective is to to compute the value of equilibrium constant, K of the reaction. Given…

Q: For the galvanic (voltaic) cell Fe(s) + Mn²⁺(aq) ⟶ Fe²⁺(aq) + Mn(s) (E° = 0.77 V at 25°C), what is…

A: Given electrochemical cell reaction equation; Fe (s) + Mn2+(aq) → Fe2+(aq) + Mn (s) Given standard…

Q: Calculate AG° for the overall redox reaction: 2x3+(aq) + 2H2O(1) → H2O2(aq) + 2H*(aq) + 2x2+(aq)…

A: Gibbs energy delta G = -nFE.

Q: For the galvanic (voltaic) cell Cd²*(aq) + Fe(s) – Cd(s) + Fe²*(aq) (E° = 0.0400 V), what is the…

A: The expression of Nernst equation is shown below: Where; Ecell= cell potential E0cell = standard…

Q: A student wishes to determine the chloride ion concentration in a water sample at 25 °C using a…

A: Given, AgCl s + e- → Ag s + Cl- aq E°red = 0.2223 V…

Q: oncentrations: [Ni²+] = 0.80M and [Co²+] = 0.20 M at 298.15 K. half-reaction Eº (V) Ni2+ (aq)…

Q: A chemist designs a galvanic cell from the following two half-reactions NO3 (aq) + 4H+ (aq) + 3e →…

Q: At 298 K, what is E (in V) for the electrochemical cell below when [Cd^2+ ]=4.700N and [Cu^2+…

Q: What is the standard cell potential for the following cell? Will the reaction be spontaneous? 3Cu(s)…

A: Given, 3Cu(s) + 2Fe3+(aq) ↔ 3Cu2+(aq) + 2Fe(s)Cu2+(aq) + 2e- ↔ Cu(s) Eo = 0.340VFe3+(aq) + 3e- ↔…

Q: 4. (a) Use the standard reduction potentials at 25° C in Table 18.1 in Tro, Fridgen and Shaw, and…

A: Step 1:

Q: Calculate Ecell (in V) for this concentration cell at 298 K. Ag(s) | Ag (aq; 0.057 M) || Ag+ (aq;…

Q: 8. Calculate Eº, E, and AG for the following cell reactions: (a) Mg(s) + Sn²+ (aq) → Mg²+(aq) +…

Q: [A4] Consider: Ag2S(ag) + Au(6) → 2Ag) + S2- + S2-(a0) + Au³+ (aq) (a) write out the reduction…

Q: voltaic cell reaction at 298 K: 3Ce4+(aq) + Cr(s) → 3Ce3+(aq) + Cr3+(aq) Given: Ce4+ (aq) + e- →…

Q: If the voltage of the cell is 0.7569 V at 25.0°C when [Mn 2+( aq)] = 0.1422 M and the pressure of H…

Q: What potential, in volts, is developed by the following electrochemical cell at 298 K? Al(s) |…

Q: When [Cu2+] = 1.24 M, the observed cell potential at 298 K for an electrochemical cell with the…

A: The overall cell reaction : Cu2+(aq) + Zn(s) ---> Cu(s) + Zn2+(aq) The observed cell potential…

Q: Which of the following statements is true concerning the electrochemical cell depicted below? M…

A: According to the representation of the given electrochemical cell the complete red-ox reaction is:…

Q: standard cell potential f

Q: 19.85 Calculate the cell potential of the following cell at 25°C. Cr(s) Cr **(1.0 x 10 ³ M) | |…

Q: half-reaction standard reduction potential MnO,(aq)+2H,0(1)+3e MnO,(s)+4 OH (aq) E=+0.59 V red 2+…

A: “Since you have posted a question with multiple sub-parts, we will solve first three sub-parts for…

Q: Consider a galvanic electrochemical cell constructed using Cr/Cr** and Zn/Zn2* at 25 °C. The…

A: In this question, we have to find out the correct answer of given problem by the help of the…

Q: Calculate the cell potential for the galvanic cell in which the reaction Ti(s) + Co² (aq) = Ti²(aq)…

A: Cell potential of any complete cell can be measured by Nernst equation. This question will be solved…

Q: The standard reduction potential E° for the reduction of permanganate in acidic solution is +1.51 V.…

A: Given, E° for reduction of permanganate in acidic solution is +1.51 V. We have to calculate the…

Q: For the galvanic (voltaic) cell Fe(s) + Mn²⁺(aq) ⟶ Fe²⁺(aq) + Mn(s) (E° = 0.77 V at 25 °C), what is…

A: Given electrochemical cell reaction equation; Fe (s) + Mn2+(aq) → Fe2+(aq) + Mn (s) Given standard…

Q: Consider the galvanic cell based on the following half-reactions. Ag+ + e− → Ag ℰ° = +0.80 V…

A: The cell's feasibility as well as potential are estimated using Nernst equation which derives the…

Q: For the galvanic (voltaic) cell Cu(s) + Mn²⁺(aq) ⟶ Cu²⁺(aq) + Mn(s) (E° = 0.60 V at 25°C), what is E…

Q: Half-reaction E° (V) Cr3+ (aq) + 3e- → Cr (s) -0.74 Fe2+ (aq) + 2e- → Fe (s) -0.440 Fe3+ (aq) + e- →…

A: Standard cell potential (E°cell) for the cell : E°cell = Ecathode - Eanode Cathode is where…

Concept explainers

Electrolysis

Electrolysis is defined as the process of breaking down ionic compounds into their constituent elements by passing a direct electric current through the compound in a fluid state. The cathode reduces cations, while the anode oxidizes anions. An electrolyte, electrodes, and some form of external power source are the main components required for conducting electrolysis. A partition, such as an ion-exchange membrane or a salt bridge, may also be used, but this is optional. These are primarily used to prevent the products from diffusing near the opposing electrode.

Question

For the galvanic (voltaic) cell Fe(s) +
Mn2* (aq) →
V at 25°C), what is [Fe2*] if [Mn²*] = 0.075
M and E = 0.78 V? Assume T is 298 K
Fe2* (aq) + Mn(s) (E° = 0.77
%3D
%3D
tv

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1 Concept

VIEW

Step 2 Calculations

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 2 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.

Similar questions

Use the Nernst equation to determine the cell potential, Ecell, of the galvanic cell consisting of the following half-cell systems: Ag+(0.010M) + e- --> Ag Eo= +0.80 V Cr3+(O.010M) + 3e- --> Cr Eo= -0.74 V
For the galvanic (voltaic) cell 2+ - Fe(s) + Mn²+ (aq) → Fe²+ (aq) + Mn(s) (E° = 0.77 V at 25 °C), what is [Fe²+] if [Mn²+] = 0.090 M and E = 0.78 V? Assume T is 298 K 1 4 7 +/- 2 LO 5 8 0.196 M 3 6 9 O X C x 100
If you said it was possible to calculate the cell voltage, do so and enter your answer here. Round your Ov answer to 2 significant digits.
Given: Half cell reaction E (V) Ag+(aq) + e- ---> Ag(s) 0.80 Cu+2(aq) + 2 e- ---> Cu(s) 0.34 Zn+2(aq) + 2 e- ---> Zn(s) -0.76 Ni+2(aq) + 2 e- ---> Ni(s) -0.23 (a) Pick up two of the above listed half-cells to build a voltaic cell that would have a maximum overall cell potential. Write the overall reaction equation. (b) Draw a detailed cell diagram and indicate which electrode is anode and which is cathode, and indicate the (-) electrode and the (+) electrode.
For the galvanic (voltaic) cell Fe(s) + Mn²⁺(aq) ⟶ Fe²⁺(aq) + Mn(s) (E° = 0.77 V at 25 °C), what is [Fe²⁺] if [Mn²⁺] = 0.030 M and E = 0.78 V? Assume T is 298 K
Plese don't provide handwritten solution
Consider the following voltaic cellat 25°C: Al(s) | Al3*(0.20 M, aq) || Al3+(0.75 M, aq) | Al(s) If the standard reduction potential for the Al3+(aq) /Al(s) redox couple is -1.66 V, what is the overall cell reaction and the cell potential of the voltaic cell shown above? (Reference the cell as written above.) The overall cell reaction is Al3+(0.75 M, aq) AIS*(0.20 M, ag) and E°cell = +0.0113 V. There is no overall cell reaction and E°cell = 0.00 V. The overall cell reaction is Al3+(0.20 M, aq) Als*(0.75 M, aq) and E°cell = +0.0113 V. The overall cell reaction is Al3+(0.20 M, aq) →A13+(0.75 M, ag) and E°cell| = -0.0113 V. The overall cell reaction is Al3*(0.75 M, aq) →AI3*(0.20 M, aq) and E°cell = -0.0113 V. None of these
For the galvanic cell at 298 K 2X(s) + 3Y2*(aq) –→ 2x3*(aq) + 3Y(s) E° cell = 0.39 V What is the measured cell potential (Ecell) when [Y2*] = 1.0 M and [X3+] = 0.01 M? Periodic Table and Datasheet O 0.39 V O 0.35 V O 0.43 V O 0.51 V
For the galvanic (voltaic) cell Cd²⁺(aq) + Fe(s) ⟶ Cd(s) + Fe²⁺(aq) (E° = 0.0400 V), what is the ratio [Fe²⁺]/[Cd²⁺] when E = 0.001 V? Assume T is 298 K
What is the balanced reaction for the following galvanic cell?Cr(s)| Cr3+(aq) || Fe3+(aq) | Fe(s) Fe(s) + Cr(s) ↔ Fe3+(aq) + Cr3+(aq) Fe3+(aq) + Cr3+(aq) ↔ Fe(s) + Cr(s) Fe3+(aq) + Cr(s) ↔ Fe(s) + Cr3+(aq) Fe(s) + Cr3+(aq) ↔ Fe3+(aq) + Cr(s)
The free energy change for the following reaction at 25 °C, when [Cu2+] = 2.57x10-³ M and [I₂] = 1.10 M, is 88.8 kJ: 2Cu²+(2.57x10-3 M) + 2.001 (aq)—2Cu+ (aq) + 1₂(1.10 M) AG= 88.8 kJ What is the cell potential for the reaction as written under these conditions? Answer: V Would this reaction be spontaneous in the forward or the reverse direction?
Which of the following reactions occurs at the anode of an electrochemical cell composed of Zn│Zn2+(aq) and Fe│Fe2+(aq) half-cells? Their reduction potentials are as follows: Zn2+ + 2e– --> Zn; Eo = -0.763 V Fe2+ + 2e– --> Fe; Eo = -0.447 V (A) Zn2+ + 2e– --> Cr; (B) Zn --> Zn2+ + 2e–; (C) Fe --> Fe2+ + 2e–; (D) Fe2+ + 2e– --> Fe;