How many metric tons of carbon are required to react with 3.96 metric tons of Fe2 O3 according to the following reaction?2 Fe2 O3 + 3 C → 3 CO2 +4Femetric tons of carbonHow many metric tons of iron are produced?metric tons of iron For the following reactions, determine the value of æ (in mol).4 C + Sg → 4 CS22.3 mol C yields x mol CS2а.molb. CS + 3 Oz СО2 + 2 SO24.5 mol CS2 yields æ mol SO2molN2H4 + 3 O2 → 2 NO2 + 2 H2O3.9 mol N2H4 yields a mol NO2C.mold. SİH4 + 2 O2 → SiO2 + 2 H202.8 × 10-8 mol SİH4 yields x mol H2Omol

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For the following reactions, determine the value of æ (in mol). 4 C + Sg → 4 CS2 2.3 mol C yields x mol CS2 а. mol b. CS + 3 Oz СО2 + 2 SO2 4.5 mol CS2 yields æ mol SO2 mol N2H4 + 3 O2 → 2 NO2 + 2 H2O 3.9 mol N2H4 yields a mol NO2 C. mol d. SİH4 + 2 O2 → SiO2 + 2 H20 2.8 × 10-8 mol SİH4 yields x mol H2O mol

For the following reactions, determine the value of æ (in mol). 4 C + Sg → 4 CS2 2.3 mol C yields x mol CS2 а. mol b. CS + 3 Oz СО2 + 2 SO2 4.5 mol CS2 yields æ mol SO2 mol N2H4 + 3 O2 → 2 NO2 + 2 H2O 3.9 mol N2H4 yields a mol NO2 C. mol d. SİH4 + 2 O2 → SiO2 + 2 H20 2.8 × 10-8 mol SİH4 yields x mol H2O mol

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

How many metric tons of carbon are required to react with 3.96 metric tons of Fe2 O3 according to the following reaction?
2 Fe2 O3 + 3 C → 3 CO2 +4Fe
metric tons of carbon
How many metric tons of iron are produced?
metric tons of iron

For the following reactions, determine the value of æ (in mol).
4 C + Sg → 4 CS2
2.3 mol C yields x mol CS2
а.
mol
b. CS + 3 Oz СО2 + 2 SO2
4.5 mol CS2 yields æ mol SO2
mol
N2H4 + 3 O2 → 2 NO2 + 2 H2O
3.9 mol N2H4 yields a mol NO2
C.
mol
d. SİH4 + 2 O2 → SiO2 + 2 H20
2.8 × 10-8 mol SİH4 yields x mol H2O
mol

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