For the following reaction, CO (g) + H2O (g) CO2 (g) + H2 (g) Kc = 1.845a. Write the Kc expression for this reaction.b. If a 1.00L vessel is charged with 0.190 moles of CO, 0.190 moles of H2O, 0.250 moles of CO2, and 0.250 moles of H2, what is the value of Q?c. In which direction does the reaction progress to establish equilibrium?d. What are the equilibrium concentration of all species?

Since you have asked a question with multiple sub-parts we will solve 1st three sub-parts. If you want an answer to remaining subparts please repost the question mentioning the subparts to be solved.We have the following reaction, CO (g) + H2O (g)------------->CO2 (g) + H2 (g) Kc = 1.845. Given: The volume of the vessel = 1.0 L. The moles of CO = 0.190 moles. The moles of H2O = 0.190 moles. The moles of CO2 = 0.250 moles. The moles of H2 = 0.250 moles. a). The expression for the Kc of the given reaction will be as follows: Q=Kc=[CO2][H2][CO][H2O].................(1) (Answer).b). The Q of the reaction is calculated using equation (1). Q=[CO2][H2][CO][H2O].................(1)Put the give values in abive equation.Q=0.25×0.250.19×0.19Q=0.06250.0361Q=1.731 (Answer)c). Since, Kc > Q, Therefore, the reaction will move in the forward direction to establish the equilibrium. (Answer)

Answered: For the following reaction, CO (g)…

Chemistry

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ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

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For the following reaction,

CO (g) + H₂O (g) CO₂ (g) + H₂ (g) Kc = 1.845

a. Write the Kc expression for this reaction.

b. If a 1.00L vessel is charged with 0.190 moles of CO, 0.190 moles of H₂O, 0.250 moles of CO₂, and 0.250 moles of H₂, what is the value of Q?

c. In which direction does the reaction progress to establish equilibrium?

d. What are the equilibrium concentration of all species?

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