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For the following reaction, 4.74 grams of butane (C,H10) are allowed to react with 20.7 grams of oxygen gas butane (C4H10)(g) + oxygen(g) → carbon dioxide(g) + water(g) What is the maximum amount of carbon dioxide that can be formed? grams What is the FORMULA for the limiting reagent?

For the following reaction, 4.74 grams of butane (C,H10) are allowed to react with 20.7 grams of oxygen gas butane (C4H10)(g) + oxygen(g) → carbon dioxide(g) + water(g) What is the maximum amount of carbon dioxide that can be formed? grams What is the FORMULA for the limiting reagent?

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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For the following reaction, 4.74 grams of butane (C,H10) are allowed to react with 20.7 grams of oxygen gas. butane (C,H10)(g) + oxygen(g) – carbon dioxide(g) + water(g) What is the maximum amount of carbon dioxide that can be formed? grams What is the FORMULA for the limiting reagent? What amount of the excess reagent remains after the reaction is complete? grams
Transcribed Image Text:For the following reaction, 4.74 grams of butane (C,H10) are allowed to react with 20.7 grams of oxygen gas. butane (C,H10)(g) + oxygen(g) – carbon dioxide(g) + water(g) What is the maximum amount of carbon dioxide that can be formed? grams What is the FORMULA for the limiting reagent? What amount of the excess reagent remains after the reaction is complete? grams
The illustration to the left represents a mixture of nitrogen ( blue ) and oxygen ( red ) molecules. If the molecules in the above illustration react to form NO according to the equation N2 + O2 → 2 NO , the limiting reagent is the number of NO molecules formed is and the number of molecules in excess is Submit Answer Retry Entire Group 2 more group attempts remaining 8.
Transcribed Image Text:The illustration to the left represents a mixture of nitrogen ( blue ) and oxygen ( red ) molecules. If the molecules in the above illustration react to form NO according to the equation N2 + O2 → 2 NO , the limiting reagent is the number of NO molecules formed is and the number of molecules in excess is Submit Answer Retry Entire Group 2 more group attempts remaining 8.
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