For the following reaction, 4.74 grams of butane (C,H10) are allowed to react with 20.7 grams of oxygen gas butane (C4H10)(g) + oxygen(g) → carbon dioxide(g) + water(g) What is the maximum amount of carbon dioxide that can be formed? grams What is the FORMULA for the limiting reagent?

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For the following reaction, 4.74 grams of butane (C,H10) are allowed to react with 20.7 grams of oxygen gas.
butane (C,H10)(g) + oxygen(g) – carbon dioxide(g) + water(g)
What is the maximum amount of carbon dioxide that can be formed?
grams
What is the FORMULA for the limiting reagent?
What amount of the excess reagent remains after the reaction is complete?
grams
Transcribed Image Text:For the following reaction, 4.74 grams of butane (C,H10) are allowed to react with 20.7 grams of oxygen gas. butane (C,H10)(g) + oxygen(g) – carbon dioxide(g) + water(g) What is the maximum amount of carbon dioxide that can be formed? grams What is the FORMULA for the limiting reagent? What amount of the excess reagent remains after the reaction is complete? grams
The illustration to the left represents a mixture of
nitrogen ( blue ) and oxygen ( red ) molecules.
If the molecules in the above illustration react to form NO according to the equation
N2 + O2 → 2 NO ,
the limiting reagent is
the number of NO molecules formed is
and
the number of
molecules in excess is
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8.
Transcribed Image Text:The illustration to the left represents a mixture of nitrogen ( blue ) and oxygen ( red ) molecules. If the molecules in the above illustration react to form NO according to the equation N2 + O2 → 2 NO , the limiting reagent is the number of NO molecules formed is and the number of molecules in excess is Submit Answer Retry Entire Group 2 more group attempts remaining 8.
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