For the following reaction, 4.59 grams of water are mixed with excess carbon monoxide. The reaction yields 8.28 grams of carbon dioxide. carbon monoxide (g) + water (1) >carbon dioxide (g) + hydrogen (g) What is the theoretical yield of carbon dioxide grams What is the percent vield of carbon dioxide ?

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For the following reaction, 4.59 grams of water are mixed with excess carbon monoxide. The reaction yields 8.28 grams of carbon dioxide.
carbon monoxide (g) + water (1) >carbon dioxide (g) + hydrogen (g)
What is the theoretical yield of carbon dioxide
grams
What is the percent vield of carbon dioxide ?
Transcribed Image Text:For the following reaction, 4.59 grams of water are mixed with excess carbon monoxide. The reaction yields 8.28 grams of carbon dioxide. carbon monoxide (g) + water (1) >carbon dioxide (g) + hydrogen (g) What is the theoretical yield of carbon dioxide grams What is the percent vield of carbon dioxide ?
Expert Solution
Step 1

Percentile yield is defined as the ratio of actual yield by theoretical yield multiplied by 100. Actual yield is the mass of the product produced in the lab while the theoretical yield is the mass of the product produced according to the mass of the reactant.

Step 2

The formula to calculate the moles of water is as follows:

Moles of water=MassMolar Mass

 

Substitute 4.59 g for mass and 18.01528 g/mol for molar mass to calculate the moles of water.

Moles of water=4.59 g18.01528 g/mol=0.254783717 mol

 

Carbon monoxide is present in excess and therefore water acts as the limiting reagent and therefore the amount of CO2 produced depends on the amount of limiting reagent water.

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