For the following program, determine the total number of items displayed, #include using namespace std; int main(){ int num = 0; while(num <= 20){ num++; cout << num << " "; } cin.ignore(); return 0; }

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
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For the following program, determine the total number of items displayed.

```cpp
#include <iostream>
using namespace std;

int main(){
    int num = 0;
    while(num <= 20){
        num++;
        cout << num << " ";
    }
    cin.ignore();
    return 0;
}
```

### Explanation:

This C++ program initializes an integer variable `num` to 0. It then enters a `while` loop, which continues to execute as long as `num` is less than or equal to 20. Within the loop:

1. The variable `num` is incremented by 1.
2. The value of `num` is printed to the console followed by a space.

After the loop completes, the `cin.ignore()` function is used to pause the program (typically to wait for user input), which is particularly helpful when running the program in environments where the console window might close immediately after execution.

- **Loop Iterations:**
  - The loop will run as long as `num` is 21 or less, so it will execute until `num` is 21.
  - `num` starts at 0 and increments before printing in each loop iteration, so the numbers 1 through 21 will be printed.

- **Output:**
  - The program will display numbers from 1 to 21, separated by spaces, resulting in a total of 21 numbers being printed.
Transcribed Image Text:For the following program, determine the total number of items displayed. ```cpp #include <iostream> using namespace std; int main(){ int num = 0; while(num <= 20){ num++; cout << num << " "; } cin.ignore(); return 0; } ``` ### Explanation: This C++ program initializes an integer variable `num` to 0. It then enters a `while` loop, which continues to execute as long as `num` is less than or equal to 20. Within the loop: 1. The variable `num` is incremented by 1. 2. The value of `num` is printed to the console followed by a space. After the loop completes, the `cin.ignore()` function is used to pause the program (typically to wait for user input), which is particularly helpful when running the program in environments where the console window might close immediately after execution. - **Loop Iterations:** - The loop will run as long as `num` is 21 or less, so it will execute until `num` is 21. - `num` starts at 0 and increments before printing in each loop iteration, so the numbers 1 through 21 will be printed. - **Output:** - The program will display numbers from 1 to 21, separated by spaces, resulting in a total of 21 numbers being printed.
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