For the following loop, assume the array arr2[][] has never been referenced before in the code. Also assume that a cache line is 32 Bytes, and an int is 4 Bytes. 1. How many memory references are there? 2. How many cache misses are there?
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For the following loop, assume the array arr2[][] has never been referenced before in
the code. Also assume that a cache line is 32 Bytes, and an int is 4 Bytes.
1. How many memory references are there?
2. How many cache misses are there?
![int arr2[1024][64]
for (i=0; i<1024; i++) {
for (j=0; j<64; j++) {
arr2[i][j] += 5](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F63744694-8781-49b6-bca2-366622d62fc9%2Fff889fc3-3a3b-458a-ab13-a8758ea32088%2Fncj6t7_processed.png&w=3840&q=75)
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- Code: #include <bits/stdc++.h> using namespace std; void BUBBLE(int A[],int N){ for(int k=0;k<N-1;++k){ for(int ptr=0;ptr<N-k-1;++ptr){ if(A[ptr]>A[ptr+1]){ int temp = A[ptr]; A[ptr] = A[ptr+1]; A[ptr+1]=temp; } } }} //function to print the arrayvoid printArray(int arr[],int n){ int i; for(i=0;i<n;i++) cout<<arr[i]<<" "; cout<<endl;} //driver function to test the modulesint main(){ int arr[] ={15,17,5,3,25,66,14,7,59,100}; int n=sizeof(arr)/sizeof(arr[0]); cout<<"\nOriginal array: "; printArray(arr,n); cout<<"\n\nOutput of Bubble sort are shown below:\n"; BUBBLE(arr,n); printArray(arr, n); return 0;} Q: Remove the Function from the above code#include<bits/stdc++.h> using namespace std; void bubbleSort(int arr[], int n) { for (int i = 0; i < n - 1; i++) { for (int j = 0; j < n - i - 1; j++) { if (arr[j] > arr[j + 1]) { int temp = arr[j]; arr[j] = arr[j + 1]; arr[j + 1] = temp; } } } } int binarySearch(int arr[], int l, int r, int x, int& comp) { comp++; if (r >= l) { int mid = l + (r - l) / 2; if (arr[mid] == x) { return mid; } if (arr[mid] > x) { return binarySearch(arr, l, mid - 1, x, comp); } return binarySearch(arr, mid + 1, r, x, comp); } return -1; } int main() { int Num[8192]; srand(time(NULL)); for (int i = 0; i < 8192; i++) { Num[i] = rand() % 10001; } clock_t starting_time = clock(); bubbleSort(Num, 8192); clock_t ending_time = clock(); clock_t result =…Figure 2 void sort_Algo (int anArray[], int n) { int i, j, idx; for (i = 0; i anArray[ idx ]) idx = j; Swap (anArray[ idx ], anArray[ i ]); } } int main() { const int n = 8; int anArray[n] { -9, 14, 52, 106, 22, -1, 99}; sort_Algo(anArray, n); } Name the sorting algorithm exercised by the sort_Algo() function. * Your answer Determine if anArray[] is to be sorted into ascending, or descending order. Your answer Trace the sorting algorithm in Figure 2 as it sorts anArray[]. (Answer the question according to the format, eg. Pass 0:3, 3, 3; Pass 1: 3, 3, 3; Pass2: 3, 3, 3;) * Your answer
- #include <bits/stdc++.h>using namespace std;#define numVl 3 struct thNde { thNde* parent; int mat[numVl][numVl]; int x, y; int cost; int level;}; int thPrntMtrx(int mat[numVl][numVl]) { for (int q = 0; q < numVl; q++) { for (int j = 0; j < numVl; j++) printf("%d ", mat[q][j]); printf("\n"); }} thNde* newNode(int mat[numVl][numVl], int x, int y, int newX, int newY, int level, thNde* parent) { thNde* node = new thNde; node->parent = parent; memcpy(node->mat, mat, sizeof node->mat); swap(node->mat[x][y], node->mat[newX][newY]); node->cost = INT_MAX; node->level = level; node->x = newX; node->y = newY; return node;} int row[] = { 1, 0, -1, 0 };int col[] = { 0, -1, 0, 1 }; int calculateCost(int starting[numVl][numVl], int resltng[numVl][numVl]) { int count = 0; for (int q = 0; q < numVl; q++) for (int j = 0; j < numVl; j++) if (starting[q][j] && starting[q][j] != resltng[q][j]) count++; return count;} int isSafe(int x, int y) {…typedef struct { short data[4];} MatrixElement; void copy_matrix(MatrixElement m1[], MatrixElement m2[], int ROWS, int COLS) { int i, j, k; for (i = 0; i < ROWS; i++) { for (j = 0; j < COLS; j++) { for (k = 0; k < 4; k++) { m1[i*COLS+j].data[k] = m2[i*COLS+j].data[k]; } } }} void copy_matrix_transpose(MatrixElement m1[], MatrixElement m2[], int ROWS, int COLS) { int i, j, k; for (i = 0; i < ROWS; i++) { for (j = 0; j < COLS; j++) { for (k = 0; k < 4; k++) { m1[i*COLS+j].data[k] = m2[j*ROWS+i].data[k]; } } }} You can assume the following conditions: The matrix m1 is allocated at memory address 0, and matrix m2 immediately follows it. Indices i, j, and k are kept in registers. ROWS and COLS are constants. The cache is initially empty before the function call. The cache is write-back (i.e., only writes back to memory when a line is…#include using namespace std; main () { int array [8] for (int x=; x> for ( cout<< return ; X< : ) : }
- array([[ 1960, 54211], [ 1961, 55438], [ 1962, 56225], [ 1963, 56695], [ 1964, 57032], [ 1965, 57360], [ 1966, 57715], [ 1967, 58055], [ 1968, 58386], [ 1969, 58726], [ 1970, 59063], [ 1971, 59440], [ 1972, 59840], [ 1973, 60243], [ 1974, 60528], [ 1975, 60657], [ 1976, 60586], [ 1977, 60366], [ 1978, 60103], [ 1979, 59980], [ 1980, 60096], [ 1981, 60567], [ 1982, 61345], [ 1983, 62201], [ 1984, 62836], [ 1985, 63026], [ 1986, 62644], [ 1987, 61833], [ 1988, 61079], [ 1989, 61032], [ 1990, 62149], [ 1991, 64622], [ 1992, 68235], [ 1993, 72504], [ 1994, 76700], [ 1995, 80324], [ 1996, 83200], [ 1997, 85451], [ 1998, 87277], [ 1999, 89005], [ 2000, 90853], [ 2001, 92898], [ 2002, 94992], [ 2003, 97017], [ 2004, 98737], [ 2005, 100031], [ 2006, 100832], [ 2007, 101220], [ 2008, 101353], [ 2009, 101453], [ 2010, 101669], [ 2011, 102053], [ 2012, 102577], [ 2013, 103187], [ 2014, 103795], [ 2015, 104341], [ 2016, 104822], [ 2017, 105264]]) Question 2 Now that we have have our…12.14 Zylab 3 - Single Procedure Call Given an array of at least one integer, write a program to create a new array with elements equal to the power of each element in the original array raised to the index, i.e., P[i] = A[i]^i. For this, write two functions that will be called in main function independently. ● power inputs: element (A[i]) and index (1) • task: returns the value of element raised to index (A[i]^i). } O • newElement inputs: base address of new array P (*P), current size of P (variable k) and the new element (A[i]^i) o task: add the new element at the end. o This function does not return any value (void). O Following is a sample C code to perform the required task. You may modify the code for the functions, but the task performed should not be changed. int main() { // Variable Declaration int *A, *P; int n, k; int pow; // Task of main function P[0] 1; for (int j = k = j; pow // Base addresses of A and P // Lengths of arrays A and B // Return value from power function }…Write c++ code for this matrix
- Solution Floating point representation: It is defined as the representation of floating numbers. It includes sign bit, exponent, and mantissa bits. Based on precision it has 2 types. 1. For IEEE 754 single-precision floating-point numbers, what is the exponent of a denormalized floating-point number in decimal? Solution: In IEEE 754 single-precision, exponent bits are 8. Therefore exponent = 2 ^(n-1) -1 = 2^(8-1) -1 = 127 OPTION D 2. For IEEE 754 single-precision floating-point numbers, how many bits for mantissa? Solution: In IEEE 754 single-precision, there are 23 bits for mantissa. sign = 1 bit exponent = 8 bits mantissa = 23 bits 3. For IEEE 754 single-precision floating-point numbers, which of the following is an example of NAN? Solution: In IEEE 754 single-precision, NAN is a special value where all exponents bits are 1's and the mantissa is non zero. a. 1 111 1 111 0000 0000 1101 0000 0000 0000 Exponent is not all 1's. Not a NAN b. 0 111 1 111 1000 0000…in c programmingConvert to C language #include <bits/stdc++.h>using namespace std; //hash function 2int main(){ int n; cout << "enter number\n"; cin >> n; //f(n)=rand()*n cout << n << "->" << (rand() * n) % 10; return 0;} Output:
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