For the dissociation of iodic acid, HIO3(aq) + H20(1) =H30*(aq) + 103 (aq) If, at equilibrium, [HIO3(aq)] = 0.16 mol L-1, [H30*(aq)] = 0.29 mol L1, and [1O3 (aq)] = 0.21 mol L1, calculate Ko. (Give 2 significant figures in your answer.) Answer:
For the dissociation of iodic acid, HIO3(aq) + H20(1) =H30*(aq) + 103 (aq) If, at equilibrium, [HIO3(aq)] = 0.16 mol L-1, [H30*(aq)] = 0.29 mol L1, and [1O3 (aq)] = 0.21 mol L1, calculate Ko. (Give 2 significant figures in your answer.) Answer:
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![For the dissociation of iodic acid,
HIO3(aq) + H20(1) H3O*(aq) + I03 (aq)
If, at equilibrium, [HIO3(aq)] = 0.16 mol L-1, [H30*(aq)] = 0.29 mol L-1, and [103 (aq)] = 0.21 mol
L1, calculate Ko. (Give 2 significant figures in your answer.)
Answer:](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F23cfaf13-27cc-434f-9074-42f27a2b7b95%2Fc6f5b0e4-3d4d-4b52-922c-4852bc47e344%2Frm2k1dj_processed.png&w=3840&q=75)
Transcribed Image Text:For the dissociation of iodic acid,
HIO3(aq) + H20(1) H3O*(aq) + I03 (aq)
If, at equilibrium, [HIO3(aq)] = 0.16 mol L-1, [H30*(aq)] = 0.29 mol L-1, and [103 (aq)] = 0.21 mol
L1, calculate Ko. (Give 2 significant figures in your answer.)
Answer:
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