### Direct Shear Stress Calculation**Problem Statement:**For the direct shear example shown below, if \( F = 47 \, \text{kN} \), \( A_{AB} = A_{CD} = 3151 \, \text{mm}^2 \), the average shear stress in the internal vertical surface AB (or CD), \( \tau = \_\_\_\_\_\ \text{MPa} \).Calculate your answer to 1 decimal place.---**Diagram Explanation:**The image shows a diagram of a 3D block structure consisting of two rectangular prisms labeled A, B, and C, with a force labeled \( F \) acting downwards on the top surface between points A and C. The force is causing a direct shear stress on the vertical internal surfaces labeled AB (or CD).**Solution:**To calculate the average shear stress (\( \tau \)):1. Use the formula for shear stress: \[ \tau = \frac{F}{A} \] where \( F \) is the force applied and \( A \) is the area over which the force is applied.2. With given values: - \( F = 47 \, \text{kN} = 47000 \, \text{N} \) - \( A = 3151 \, \text{mm}^2 = 0.003151 \, \text{m}^2 \)3. Substitute the values: \[ \tau = \frac{47000}{0.003151} = 14916.22 \, \text{Pa} = 14.9 \, \text{MPa} \]4. Calculate to 1 decimal place: \[ \tau = 14.9 \, \text{MPa} \]Thus, the average shear stress on the internal vertical surface AB (or CD) is **14.9 MPa**.

Answered: For the direct shear example shown…

For the direct shear example shown below, if F = 47 kN, AAB = AcD = 3151 mm², the average shear stress in the internal vertical surface AB CD), t = MPa. Calculate your answer to 1 decimal place.

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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