For the curve y = f(x) = x², 0 ≤ x ≤ 2, its length is 2 L = 1+ dy dx dx =

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Example
For the curve y = f(x) = x², 0 < x< 2, its length is
%3D
dy
1+
dx
dx
%3D
Transcribed Image Text:Example For the curve y = f(x) = x², 0 < x< 2, its length is %3D dy 1+ dx dx %3D
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but for the answer there is no denominator 5

O MAT203 VECTOR CALCULUS
i elearning.usm.my/sidang2122/pluginfile.php/597533/mod_resource/content/1/12%20Apr%202022.pdf
* O
MAT203 VECTOR CALCULUS
6 / 28
175%
+ |
Example
For the curve y = f(x) = x², 0 <x < 2, its length is
2
dy
1+
dx
VI7).
dx
4/17+ In (4 + v
0.
If we consider
s(x) = V1+ (F'(t))² dt
2.xV1+ 4x2 + ln |2x + V1+ 4x²| )
then
s(1) - 1.47894
and
s(2) - 4.64678.
Arc length
Surface area
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Arc length function
2:38 AM
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26°C Light rain
IMI
20/4/2022
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ENG
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Transcribed Image Text:O MAT203 VECTOR CALCULUS i elearning.usm.my/sidang2122/pluginfile.php/597533/mod_resource/content/1/12%20Apr%202022.pdf * O MAT203 VECTOR CALCULUS 6 / 28 175% + | Example For the curve y = f(x) = x², 0 <x < 2, its length is 2 dy 1+ dx VI7). dx 4/17+ In (4 + v 0. If we consider s(x) = V1+ (F'(t))² dt 2.xV1+ 4x2 + ln |2x + V1+ 4x²| ) then s(1) - 1.47894 and s(2) - 4.64678. Arc length Surface area 0000000O 00000000o00000000 Arc length function 2:38 AM O Type here to search 26°C Light rain IMI 20/4/2022 O ENG > ... ... i! II
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