For the cross-section area is shown below, the centroid (in mm) measured from the base is equal to: Y =note: just Vertical direction40 mm5 mm50 mmY=-5 mm5 mm20mm2512.733528.5

Answered: For the cross-section area is shown…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Concept explainers

Question

For the cross-section area is shown below, the centroid (in mm) measured from the base is equal to: Y =
note: just Vertical direction
40 mm
5 mm
50 mm
Y=
-5 mm
5 mm
20
mm
25
12.73
35
28.5

Expert Solution

Step 1

To find CG divide I section in three parts as bottom flange as first part ,web as second part and top flange as third part

$CG is given by \bar{Y} = \frac{A_{1} Y_{1} + A_{2} Y_{2} + A_{3} Y_{3}}{A_{1} + A_{2} + A_{3}} Here A_{1}, A_{2}, A_{3} are area of each part Y_{1}, Y_{2}, Y_{3} is distance of CG of each area from bottom So directly putting values in above equation \bar{Y} = \frac{20 \times 5 \times 2.5 + 5 \times 50 \times 30 + 40 \times 5 \times 57.5}{20 \times 5 + 5 \times 50 + 5 \times 40} \bar{Y} = 35 mm$

Step by step

Solved in 2 steps

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.

Similar questions