I did the question but wasnt sure if I am following the question correctly, as such I need help 8. Fo8. For the configuration of Fig. 8.100:a. Convert the current source and 6.8- resistorvoltage source.b. Find the magnitude and direction of the currentc. Find the voltage Vab and the polarity of points aR₁+₁10 ΩE 12 VR₂www6.8 Ω1 = 2 A1₁FIG. 8.100Problem 8.R339 Ω Τb

For the configuration of Fig. 8.100: a. Convert the current source and 6.8-2 resistor voltage source. b. Find the magnitude and direction of the current c. Find the voltage Vab and the polarity of points a Ε' R₁ www 10 Ω 4₁ 12 V R₂ ww 6.8 Ω 1 = 2 A 1₁ FIG. 8.100 Problem 8 R₂39 V Ω

For the configuration of Fig. 8.100: a. Convert the current source and 6.8-2 resistor voltage source. b. Find the magnitude and direction of the current c. Find the voltage Vab and the polarity of points a Ε' R₁ www 10 Ω 4₁ 12 V R₂ ww 6.8 Ω 1 = 2 A 1₁ FIG. 8.100 Problem 8 R₂39 V Ω

Delmar's Standard Textbook Of Electricity

7th Edition

ISBN:9781337900348

Author:Stephen L. Herman

Publisher:Stephen L. Herman

Chapter18: Resistive-inductive Parallel Circuits

Section: Chapter Questions

Problem 10PP: In an R-L parallel circuit, ET=240 volts, R=560, and XL=330. Find apparent power.

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Concept explainers

Wheatstone Bridge Method

A Wheatstone bridge is a circuit used to measure unknown resistance by measuring the ratios of the two branches of the circuit such that each branch has two resistance and out of four resistance one is unknown. The two branches are joined in between with the help of galvanometer which is used to determine the direction of the current. The main advantage of this circuit is that it can provide the most accurate measurement (different from a simple voltage separator).

Question

I did the question but wasnt sure if I am following the question correctly, as such I need help

8. Fo
8. For the configuration of Fig. 8.100:
a. Convert the current source and 6.8- resistor
voltage source.
b. Find the magnitude and direction of the current
c. Find the voltage Vab and the polarity of points a
R₁
+₁
10 Ω
E 12 V
R₂
www
6.8 Ω
1 = 2 A
1₁
FIG. 8.100
Problem 8.
R3
39 Ω Τ
b

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