For the circuit shown, ZL = 50 – j30 N. What component is needed to form impedance ZPFC in parallel with ZL such that %3D - the load achieves unity power factor? 5520° V ZL ZPFC f = 110 Hz
For the circuit shown, ZL = 50 – j30 N. What component is needed to form impedance ZPFC in parallel with ZL such that %3D - the load achieves unity power factor? 5520° V ZL ZPFC f = 110 Hz
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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Transcribed Image Text:**Unity Power Factor Circuit Design**
For the circuit shown, the load impedance \(Z_L\) is given as \(50 - j30 \, \Omega\). The objective is to determine the component needed to form the impedance \(Z_{PFC}\) in parallel with \(Z_L\) so that the load achieves unity power factor.
**Circuit Details:**
- The circuit is supplied by a voltage source of \(55 \angle 0^\circ \, \text{V}\).
- Frequency of the source, \(f = 110 \, \text{Hz}\).
**Diagram Explanation:**
The diagram displays a simple electrical circuit with the following elements:
1. **Voltage Source:**
- Denoted by the sinusoidal symbol.
- Voltage: \(55 \angle 0^\circ \, \text{V}\).
2. **Load Impedance (\(Z_L\)):**
- Represented as a rectangular block.
- Impedance: \(50 - j30 \, \Omega\).
3. **Power Factor Correction Impedance (\(Z_{PFC}\)):**
- Another rectangular block placed parallel to \(Z_L\).
- The component required to achieve unity power factor needs to be determined.
**Objective:**
To achieve a unity power factor, the imaginary part (reactive component) of the total impedance must be zero. This can be done by selecting a component that introduces a compensating reactance in the \(Z_{PFC}\) branch.
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