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For the circuit shown, what is the complex power, S, consumed by the 18 + j32 load impedance? (Assume the voltage source is in RMS.) 30 j8 N 18 0 = 25 20° V j32 0 39.84/29.4° VA O 33.61/27.7° VA O 11.24260.6° VA O 17.02/ - 64.0° VA 10

For the circuit shown, what is the complex power, S, consumed by the 18 + j32 load impedance? (Assume the voltage source is in RMS.) 30 j8 N 18 0 = 25 20° V j32 0 39.84/29.4° VA O 33.61/27.7° VA O 11.24260.6° VA O 17.02/ - 64.0° VA 10

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
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**Circuit Analysis: Calculating Complex Power** **Problem Statement:** For the circuit shown, what is the complex power, \( S \), consumed by the \( 18 + j32 \, \Omega \) load impedance? (Assume the voltage source is in RMS.) **Diagram Explanation:** The circuit contains the following components: - A voltage source \( \tilde{V}_s = 25\angle 0^\circ \, \text{V} \). - A resistor with \( 3 \, \Omega \). - An inductor with impedance \( j8 \, \Omega \). - A load impedance of \( 18 + j32 \, \Omega \). Connections: - The components are connected in series, starting with the voltage source and moving through the \( 3 \, \Omega \) resistor, the \( j8 \, \Omega \) inductor to point \( a \). - The circuit continues from point \( a \) through the series load \( 18 + j32 \, \Omega \) to point \( b \), then completing the loop back to the voltage source. **Options for the Complex Power:** 1. \( 39.84\angle 29.4^\circ \, \text{VA} \) 2. \( 33.61\angle 27.7^\circ \, \text{VA} \) 3. \( 11.24\angle 60.6^\circ \, \text{VA} \) 4. \( 17.02\angle -64.0^\circ \, \text{VA} \)
Transcribed Image Text:**Circuit Analysis: Calculating Complex Power** **Problem Statement:** For the circuit shown, what is the complex power, \( S \), consumed by the \( 18 + j32 \, \Omega \) load impedance? (Assume the voltage source is in RMS.) **Diagram Explanation:** The circuit contains the following components: - A voltage source \( \tilde{V}_s = 25\angle 0^\circ \, \text{V} \). - A resistor with \( 3 \, \Omega \). - An inductor with impedance \( j8 \, \Omega \). - A load impedance of \( 18 + j32 \, \Omega \). Connections: - The components are connected in series, starting with the voltage source and moving through the \( 3 \, \Omega \) resistor, the \( j8 \, \Omega \) inductor to point \( a \). - The circuit continues from point \( a \) through the series load \( 18 + j32 \, \Omega \) to point \( b \), then completing the loop back to the voltage source. **Options for the Complex Power:** 1. \( 39.84\angle 29.4^\circ \, \text{VA} \) 2. \( 33.61\angle 27.7^\circ \, \text{VA} \) 3. \( 11.24\angle 60.6^\circ \, \text{VA} \) 4. \( 17.02\angle -64.0^\circ \, \text{VA} \)
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