For the circuit shown, the voltage drop across resistor R3 would be: IT VT= 120 V IT 1₁ R1 = 532 R3 = 682 3 12 R2 = 2022

Q: In given figure, What is the value of resistance R in a? BA 1oov UIO OL WW- 10 Ohm ww-

A: so for the first question we will use  ohms law to get the required resistance. for second question…

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Q: Using superposition solve for the current and voltage at R3. R1 R2 100 70 V1 Ix 11 6A 10V R3 30

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Q: Numeric 4) VT= 5) V2= 6) V3 =

A: To solve above problem, we will use Ohm's law and Kirchhoff's law: Ohm's law state that in a current…

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Q: IT R2= 220 12 13 14 R1 = 600 R3 = 100 R4= 40a 30 V

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Q: XFor the circuit shown in the figure, what is the current through resistor R1? R1 (70.0N) R2(105.0…

A: This question belongs to circuit theory . It is based on the concept of kvl and kcl in the circuit .…

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Q: 7) Using Kirchoff's Laws to solve the current across each resistor in the circuit below Vs 10V R1…

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Q: currents and powers

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Q: For the following circuit determine each of the currents I1, I2, I3, I4 and the resistance R3

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Q: Problem 2: Thevenin's equivalent circuit 2502 3002 4002 5000 20V 3002 10V 2000 °B

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Q: R1 Si V1 Ge 3kQ 8 V R2 2kQ VGe R3 i2 4ka

A: The solution to all three subparts is attached in the following steps.

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A: Req=6+4∥3+12Req=6 ΩI=15Req=156=2.5 A Current division rule: I=total current ×resistance of parallel…

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A: i) For t < 3ms S1 and S2  Vc(3 ms) =0 V Current through S1  = 0 A

Q: For the circuit shown the value of 13 would For the circuit shown the value of 13 would be: 12 A R1…

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Q: Refer to the given circuit. R2 = 5 0 R = 6 2 %3D R3 = 4 N R4 = 4 2 R5 = 8 0 DURACELL VT = 10 V

A: We need to find out voltage across the resistor

Q: 9v + 1 I1 = 20mA 3.3v R1 =? 2.2v 12 =? ww R2 = 100ohms 1.7v 13 = 100mA R3 =?

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Q: 6² V₁ V₂ T BRa Vs the Rost Given R₂=122 R3=52 √3-6V R4=92 P₁ = 352 R5 = 82 V² = 17v V₂ = 45°v

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Power Measurement

According to Blondel's theorem, the total power is measured with one less number of wattmeters than the number of wires present in the system. So, a single-phase and two-wire system will require one wattmeter and a single-phase and the three-wire system will require two wattmeters, and a three-phase and the three-wire system will also require two wattmeters and a three-phase and the four-wire system will require three wattmeter devices. The wattmeter is a device that measures power using one voltage and one current input as shown in the above figure. Multiple current or voltage input pair cables are used by many power analyzers and digital storage oscilloscopes (DSOs) for measuring watts, in effect within a single instrument acting as multiple wattmeters. It is possible to measure three-phase and four-wire power with one correctly specified power analyzer.