For the circuit shown, the energy stored by the 2.0 µF capacitor is 0.40 mJ. Find the voltage (in V) across the 5.0 μF capacitor. 2.0 µF 4.0 μF 3.0 µF 5.0 μF 6.0 µF ¡I 5.20 DM 11
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The charge which is accumulated on a conductor is directly proportional to potential difference applied across it.
This is given as
Here is called the capacitance of the conductor.
This capacitance is unique property which is the capacity to hold charges.
The concept of wheatstone bridge can be applied in case of capacitors also. Here the resistances are replaced by capacitors.
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