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For the circuit shown, the energy stored by the 2.0 µF capacitor is 0.40 mJ. Find the voltage (in V) across the 5.0 μF capacitor. 2.0 µF 4.0 μF 3.0 µF 5.0 μF 6.0 µF ¡I 5.20 DM 11

For the circuit shown, the energy stored by the 2.0 µF capacitor is 0.40 mJ. Find the voltage (in V) across the 5.0 μF capacitor. 2.0 µF 4.0 μF 3.0 µF 5.0 μF 6.0 µF ¡I 5.20 DM 11

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ع *** سلام Saved Messages Batool almomani Batool momani | MW_Batool MW_Batool Message بتول المومني بتول مومني بطرونة تيليجرام البطرونة بتول المومني البطرونة بتول مومني For the circuit shown, the energy stored by the 2.0 µF capacitor is 0.40 mJ. Find the voltage (in V) across the 5.0 μµF capacitor. 2.0 F HE 4.0 F 11:35 AM 5.0 ۴ بشتغل في جروب تيليجرام بخلي الشباب تمرج ع صوتي 3.0 F 6.0 F : I.DA D / 2
Transcribed Image Text:ع *** سلام Saved Messages Batool almomani Batool momani | MW_Batool MW_Batool Message بتول المومني بتول مومني بطرونة تيليجرام البطرونة بتول المومني البطرونة بتول مومني For the circuit shown, the energy stored by the 2.0 µF capacitor is 0.40 mJ. Find the voltage (in V) across the 5.0 μµF capacitor. 2.0 F HE 4.0 F 11:35 AM 5.0 ۴ بشتغل في جروب تيليجرام بخلي الشباب تمرج ع صوتي 3.0 F 6.0 F : I.DA D / 2
Expert Solution
Introduction:

The charge which is accumulated on a conductor is directly proportional to potential difference applied across it.

This is given as

Q∝VQ=CV

Here C is called the capacitance of the conductor.

This capacitance is unique property which is the capacity to hold charges.

The concept of wheatstone bridge can be applied in case of capacitors also. Here the resistances are replaced by capacitors.

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