Each capacitor in the combination shown in the figure below (C = 17.0 μF) has a breakdown voltage of 13.0 V. What is the breakdown voltage of the combination? 20.0 με a V 20.0μF C 20.0 με 20.0 με
Each capacitor in the combination shown in the figure below (C = 17.0 μF) has a breakdown voltage of 13.0 V. What is the breakdown voltage of the combination? 20.0 με a V 20.0μF C 20.0 με 20.0 με
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
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its not 39 volts it need to have a decimal like 12.1 or 13.1
![## Capacitor Breakdown Voltage Calculation
**Question:**
Each capacitor in the combination shown in the figure below (\( C = 17.0 \, \mu\text{F} \)) has a breakdown voltage of \( 13.0 \, \text{V} \). What is the breakdown voltage of the combination?
**Diagram:**
The diagram consists of a combination of capacitors arranged as follows:
1. On the left side, there are two parallel capacitors, each of \( 20.0 \, \mu\text{F} \). This combination is connected to point \( a \).
2. In the middle, there is a single capacitor \( C \) with a capacitance of \( 17.0 \, \mu\text{F} \).
3. On the right side, this middle capacitor is connected to two parallel capacitors, each again of \( 20.0 \, \mu\text{F} \). This combination is connected to point \( b \).
**Schematic Layout:**
- Point \( a \)
- | 20.0 μF |
- | 20.0 μF |
- \( C \) (17.0 μF)
- Point \( b \)
- | 20.0 μF |
- | 20.0 μF |
**Answer Box:**
\( \text{Voltage} = \) [ ] \( \text{V} \)
---
**Explanation:**
To find the breakdown voltage of the entire combination, consider how the capacitors are connected and the fundamental principle that the voltage across capacitors in parallel is the same, while the voltages of capacitors in series add up.
The parallel combinations on both sides each can handle the same breakdown voltage as the individual capacitors, \( 13.0 \, \text{V} \).
In the series combination:
- Middle capacitor has a breakdown voltage of \( 13.0 \, \text{V} \).
- Each parallel side can handle \( 13.0 \, \text{V} \).
Therefore, the breakdown voltage of the entire combination is:
\[ 13.0 \, \text{V} + 13.0 \, \text{V} + 13.0 \, \text{V} = 39.0 \, \text{V} \]
**Result:](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F75edd112-ce06-4202-807b-82434248c0a2%2Ff186678d-f446-44fe-ad51-f2844498ae36%2F6hw6ka_processed.png&w=3840&q=75)
Transcribed Image Text:## Capacitor Breakdown Voltage Calculation
**Question:**
Each capacitor in the combination shown in the figure below (\( C = 17.0 \, \mu\text{F} \)) has a breakdown voltage of \( 13.0 \, \text{V} \). What is the breakdown voltage of the combination?
**Diagram:**
The diagram consists of a combination of capacitors arranged as follows:
1. On the left side, there are two parallel capacitors, each of \( 20.0 \, \mu\text{F} \). This combination is connected to point \( a \).
2. In the middle, there is a single capacitor \( C \) with a capacitance of \( 17.0 \, \mu\text{F} \).
3. On the right side, this middle capacitor is connected to two parallel capacitors, each again of \( 20.0 \, \mu\text{F} \). This combination is connected to point \( b \).
**Schematic Layout:**
- Point \( a \)
- | 20.0 μF |
- | 20.0 μF |
- \( C \) (17.0 μF)
- Point \( b \)
- | 20.0 μF |
- | 20.0 μF |
**Answer Box:**
\( \text{Voltage} = \) [ ] \( \text{V} \)
---
**Explanation:**
To find the breakdown voltage of the entire combination, consider how the capacitors are connected and the fundamental principle that the voltage across capacitors in parallel is the same, while the voltages of capacitors in series add up.
The parallel combinations on both sides each can handle the same breakdown voltage as the individual capacitors, \( 13.0 \, \text{V} \).
In the series combination:
- Middle capacitor has a breakdown voltage of \( 13.0 \, \text{V} \).
- Each parallel side can handle \( 13.0 \, \text{V} \).
Therefore, the breakdown voltage of the entire combination is:
\[ 13.0 \, \text{V} + 13.0 \, \text{V} + 13.0 \, \text{V} = 39.0 \, \text{V} \]
**Result:
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