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For the circuit shown in below figure, find v and the power absorbed by the resistor 15 mA V O a. 90 V and 675 mW O b. 45 V and 675 mW O c. 5 V and 675 W O d. 45 mV and 675 mW O e. 45 V and 675 W {3 ΚΩ

For the circuit shown in below figure, find v and the power absorbed by the resistor 15 mA V O a. 90 V and 675 mW O b. 45 V and 675 mW O c. 5 V and 675 W O d. 45 mV and 675 mW O e. 45 V and 675 W {3 ΚΩ

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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**Problem Statement:** For the circuit shown in below figure, find \( v \) and the power absorbed by the resistor? **Circuit Diagram:** The diagram consists of a simple circuit with a current source and a resistor. The components are as follows: - A current source of \( 15 \text{ mA} \) is connected in series with a resistor of \( 3 \text{ k}\Omega \). - The node voltages across the resistor are marked as \( +v \) and \(-v \), indicating a potential difference that we need to find. **Multiple Choice Answers:** - a. \( 90 \text{ V} \) and \( 675 \text{ mW} \) - b. \( 45 \text{ V} \) and \( 675 \text{ mW} \) - c. \( 5 \text{ V} \) and \( 675 \text{ W} \) - d. \( 45 \text{ mV} \) and \( 675 \text{ mW} \) - e. \( 45 \text{ V} \) and \( 675 \text{ W} \) **Explanation:** To solve for \( v \) and the power absorbed by the resistor, follow these steps: 1. **Calculate Voltage \( v \):** - Use Ohm’s Law \( V = IR \), where \( I = 15 \text{ mA} = 0.015 \text{ A} \) and \( R = 3 \text{ k}\Omega = 3000 \Omega \). \[ V = I \times R = 0.015 \text{ A} \times 3000 \Omega = 45 \text{ V} \] 2. **Calculate Power Absorbed by the Resistor:** - Use the formula for power \( P = V \times I \). \[ P = 45 \text{ V} \times 0.015 \text{ A} = 0.675 \text{ W} = 675 \text{ mW} \] **Answer:** The correct option is: - b. \( 45 \text{ V} \) and \( 675 \text{ mW} \)
Transcribed Image Text:**Problem Statement:** For the circuit shown in below figure, find \( v \) and the power absorbed by the resistor? **Circuit Diagram:** The diagram consists of a simple circuit with a current source and a resistor. The components are as follows: - A current source of \( 15 \text{ mA} \) is connected in series with a resistor of \( 3 \text{ k}\Omega \). - The node voltages across the resistor are marked as \( +v \) and \(-v \), indicating a potential difference that we need to find. **Multiple Choice Answers:** - a. \( 90 \text{ V} \) and \( 675 \text{ mW} \) - b. \( 45 \text{ V} \) and \( 675 \text{ mW} \) - c. \( 5 \text{ V} \) and \( 675 \text{ W} \) - d. \( 45 \text{ mV} \) and \( 675 \text{ mW} \) - e. \( 45 \text{ V} \) and \( 675 \text{ W} \) **Explanation:** To solve for \( v \) and the power absorbed by the resistor, follow these steps: 1. **Calculate Voltage \( v \):** - Use Ohm’s Law \( V = IR \), where \( I = 15 \text{ mA} = 0.015 \text{ A} \) and \( R = 3 \text{ k}\Omega = 3000 \Omega \). \[ V = I \times R = 0.015 \text{ A} \times 3000 \Omega = 45 \text{ V} \] 2. **Calculate Power Absorbed by the Resistor:** - Use the formula for power \( P = V \times I \). \[ P = 45 \text{ V} \times 0.015 \text{ A} = 0.675 \text{ W} = 675 \text{ mW} \] **Answer:** The correct option is: - b. \( 45 \text{ V} \) and \( 675 \text{ mW} \)
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