For the circuit in Figure 1: a) Determine the equivalent capacitance of the system. b) If the potential difference between point a and b is 100 V, determine the stored charge of the 10 µF capacitor c) If all the capacitors initially had air and now they have been put as a graphic dielectric material (K = 12.5), what is the difference in charge of the 6 µF capacitor near point b? 4.0 μF 4.0 µF v 10.0 µF T7.0 µF 5.0 µF |7.0 μF 5.0 µF a b 6.0 µF 6.0 µF Figure 1.
For the circuit in Figure 1: a) Determine the equivalent capacitance of the system. b) If the potential difference between point a and b is 100 V, determine the stored charge of the 10 µF capacitor c) If all the capacitors initially had air and now they have been put as a graphic dielectric material (K = 12.5), what is the difference in charge of the 6 µF capacitor near point b? 4.0 μF 4.0 µF v 10.0 µF T7.0 µF 5.0 µF |7.0 μF 5.0 µF a b 6.0 µF 6.0 µF Figure 1.
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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Solve what is presented below in relation to the image provided (All the exercise comes in the image).
Solve the 3 items that is a, b and c.
Put step by step to get to the result.
For the circuit in Figure 1:
a) Determine the equivalent capacitance of the system.
b) If the potential difference between point a and b is 100 V, determine the stored charge of the 10 uF capacitor
c) If all the capacitors initially had air and now they have been put as a graphic dielectric material (k= 12.5), what is the difference in charge of the 6uF capacitor near point b?
Transcribed Image Text:For the circuit in Figure 1:
a) Determine the equivalent capacitance of the system.
b) If the potential difference between point a and b is 100 V, determine the stored charge
of the 10 µF capacitor
c) If all the capacitors initially had air and now they have been put as a graphic dielectric
material (K = 12.5), what is the difference in charge of the 6 µF capacitor near point b?
4.0 μF
4.0 µF v
10.0 µF
7.0 µF
5.0 µF
|7.0 μF
5.0 µF
a
6.0 µF
6.0 µF
Figure 1.
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