I need the answer with explain pls For the circuit in fig.1, if Rs is equal to 600 Q, find FL.20 V= 7 pF Che 6 pFCw 11 pF Che= 20 pFCee 10 pF%3D3 k2470 k21 µFV&B 1001 µF4.7 k20.91 k26.8 µFFigure 1

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Answered: For the circuit in fig.1, if Rs is…

For the circuit in fig.1, if Rs is equal to 600 2, find FL. 20 V Cw, = 7 pF Ce 6 pF Cw = 11 pF Che= 20 pF Cee 10 pF %3D 3 k2 470 k2 1 µF Ve B 100 1 µF 4.7 k2 0.91 k2 6.8 uF Figure 1

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

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Concept explainers

Code Conversion

The method or technique used to convert code from one format to another is termed code conversion. Code conversions are most commonly used in computers, digital electronics, microprocessors, etc.

Question

I need the answer with explain pls

For the circuit in fig.1, if Rs is equal to 600 Q, find FL.
20 V
= 7 pF Che 6 pF
Cw 11 pF Che= 20 pF
Cee 10 pF
%3D
3 k2
470 k2
1 µF
V&
B 100
1 µF
4.7 k2
0.91 k2
6.8 µF
Figure 1

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