For the circuit in fig.1, if Rs is equal to 600 2, find FL. 20 V Cw, = 7 pF Ce 6 pF Cw = 11 pF Che= 20 pF Cee 10 pF %3D 3 k2 470 k2 1 µF Ve B 100 1 µF 4.7 k2 0.91 k2 6.8 uF Figure 1

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For the circuit in fig.1, if Rs is equal to 600 Q, find FL.
20 V
= 7 pF Che 6 pF
Cw 11 pF Che= 20 pF
Cee 10 pF
%3D
3 k2
470 k2
1 µF
V&
B 100
1 µF
4.7 k2
0.91 k2
6.8 µF
Figure 1
Transcribed Image Text:For the circuit in fig.1, if Rs is equal to 600 Q, find FL. 20 V = 7 pF Che 6 pF Cw 11 pF Che= 20 pF Cee 10 pF %3D 3 k2 470 k2 1 µF V& B 100 1 µF 4.7 k2 0.91 k2 6.8 µF Figure 1
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