Homework Help is Here – Start Your Trial Now!
Engineering
Electrical Engineering
For the circuit below, The determine the voltage ratio Vo/V3 : (Provide your calculations and reasoning for your answer.) U2 R4 OUT OFAMP V3 R7 500 US V. R5 OUT OPAMP RS R10

For the circuit below, The determine the voltage ratio Vo/V3 : (Provide your calculations and reasoning for your answer.) U2 R4 OUT OFAMP V3 R7 500 US V. R5 OUT OPAMP RS R10

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
See similar textbooks
icon
Related questions
Question
For the circuit below, determine the voltage ratio \( V_o/V_3 \). (Provide your calculations and reasoning for your answer.) **Circuit Description:** The circuit consists of two operational amplifiers (op-amps), labeled U2 and U3, with resistors connected in the following configuration: 1. **U2 Op-Amp:** - Non-inverting input is grounded. - Inverting input is connected to a voltage source \( V_3 \) via resistor \( R4 \) (1kΩ). - Feedback loop with resistor \( R5 \) (1kΩ) connecting the output back to the inverting input. - Output connected to resistor \( R7 \) (500Ω). 2. **U3 Op-Amp:** - Non-inverting input is grounded. - Inverting input connected to the output of U2 via resistor \( R7 \) (500Ω). - Feedback loop with resistor \( R10 \) (1kΩ) connecting the output back to the inverting input. - Resistor \( R9 \) (1kΩ) connected from the inverting input of U3 to ground. - Output labeled as \( V_o \). **Analysis:** - First Op-Amp (U2): Configured as an inverting amplifier with equal resistors \( R4 \) and \( R5 \), resulting in a gain of -1. - Second Op-Amp (U3): Configured as an inverting amplifier with resistors \( R9 \) and \( R10 \). The gain is given by \(-R10/R9 = -1\). **Calculations:** 1. \( V_{out2} = -\left(\frac{R5}{R4}\right) \times V_3 = -V_3 \). 2. \( V_o = -\left(\frac{R10}{R9}\right) \times V_{out2} = -(-V_3) = V_3 \). **Voltage Ratio:** \[ \frac{V_o}{V_3} = \frac{V_3}{V_3} = 1 \] The voltage ratio \( V_o/V_3 \) is calculated to be 1.
Transcribed Image Text:For the circuit below, determine the voltage ratio \( V_o/V_3 \). (Provide your calculations and reasoning for your answer.) **Circuit Description:** The circuit consists of two operational amplifiers (op-amps), labeled U2 and U3, with resistors connected in the following configuration: 1. **U2 Op-Amp:** - Non-inverting input is grounded. - Inverting input is connected to a voltage source \( V_3 \) via resistor \( R4 \) (1kΩ). - Feedback loop with resistor \( R5 \) (1kΩ) connecting the output back to the inverting input. - Output connected to resistor \( R7 \) (500Ω). 2. **U3 Op-Amp:** - Non-inverting input is grounded. - Inverting input connected to the output of U2 via resistor \( R7 \) (500Ω). - Feedback loop with resistor \( R10 \) (1kΩ) connecting the output back to the inverting input. - Resistor \( R9 \) (1kΩ) connected from the inverting input of U3 to ground. - Output labeled as \( V_o \). **Analysis:** - First Op-Amp (U2): Configured as an inverting amplifier with equal resistors \( R4 \) and \( R5 \), resulting in a gain of -1. - Second Op-Amp (U3): Configured as an inverting amplifier with resistors \( R9 \) and \( R10 \). The gain is given by \(-R10/R9 = -1\). **Calculations:** 1. \( V_{out2} = -\left(\frac{R5}{R4}\right) \times V_3 = -V_3 \). 2. \( V_o = -\left(\frac{R10}{R9}\right) \times V_{out2} = -(-V_3) = V_3 \). **Voltage Ratio:** \[ \frac{V_o}{V_3} = \frac{V_3}{V_3} = 1 \] The voltage ratio \( V_o/V_3 \) is calculated to be 1.
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps with 2 images

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer
Knowledge Booster
Nodal analysis
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, electrical-engineering and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
Electrical Engineering
ISBN:
9780133923605
Author:
Robert L. Boylestad
Publisher:
PEARSON
Delmar's Standard Textbook Of Electricity
Delmar's Standard Textbook Of Electricity
Electrical Engineering
ISBN:
9781337900348
Author:
Stephen L. Herman
Publisher:
Cengage Learning
Programmable Logic Controllers
Programmable Logic Controllers
Electrical Engineering
ISBN:
9780073373843
Author:
Frank D. Petruzella
Publisher:
McGraw-Hill Education
Fundamentals of Electric Circuits
Fundamentals of Electric Circuits
Electrical Engineering
ISBN:
9780078028229
Author:
Charles K Alexander, Matthew Sadiku
Publisher:
McGraw-Hill Education
Electric Circuits. (11th Edition)
Electric Circuits. (11th Edition)
Electrical Engineering
ISBN:
9780134746968
Author:
James W. Nilsson, Susan Riedel
Publisher:
PEARSON
Engineering Electromagnetics
Engineering Electromagnetics
Electrical Engineering
ISBN:
9780078028151
Author:
Hayt, William H. (william Hart), Jr, BUCK, John A.
Publisher:
Mcgraw-hill Education,
SEE MORE TEXTBOOKS