For the circuit above: B(t+1) equation can be expressed as B(t+1)= E(3,8,15) Β (t+1 )- Σ(6,7,1 5) Β(t+1 )-Σ(3,6,7) Β(t+1)- Σ(6,7,8, 1 5) B(t+1)- Σ(7,8, 1 2) For the circuit above. What is a Boolean expression for z? АВху ABx'y`+ ABXY АВ ABx+ Bx'y` ABx'y`
For the circuit above: B(t+1) equation can be expressed as B(t+1)= E(3,8,15) Β (t+1 )- Σ(6,7,1 5) Β(t+1 )-Σ(3,6,7) Β(t+1)- Σ(6,7,8, 1 5) B(t+1)- Σ(7,8, 1 2) For the circuit above. What is a Boolean expression for z? АВху ABx'y`+ ABXY АВ ABx+ Bx'y` ABx'y`
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
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Question
For the circuit above: B(t+1) equation can be expressed as
![1
For the state diagram below state 1 is 00,
state 2 is 01, state 3 -10, state 4 -11.Input
variables are x and y, output function is z. For
the implementation JK flip-flops A(MSB) and
B are used.
00/1
10/0
01/0
11/0
W 110
11/0
00/0
0/10
2
3
100
000
11/0
01/0
100
10/0](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7d3e2a9d-ac86-4edb-bef9-bef68c8bc1cf%2Fdae5bd10-9745-4772-a762-c9e93fe2757f%2Fjj1qc4b_processed.jpeg&w=3840&q=75)
Transcribed Image Text:1
For the state diagram below state 1 is 00,
state 2 is 01, state 3 -10, state 4 -11.Input
variables are x and y, output function is z. For
the implementation JK flip-flops A(MSB) and
B are used.
00/1
10/0
01/0
11/0
W 110
11/0
00/0
0/10
2
3
100
000
11/0
01/0
100
10/0
![7
For the circuit above: B(t+1) equation can be
expressed as
B(t+1)= E(3,8,15)
Β (+1)-Σ(6,7,1 5)
B(t+1)= E(3,6,7)
B((+1)-Σ(6,7,8, 1 5)
B((+1)-Σ(7,8, 1 2)
8
For the circuit above. What is a Boolean
expression for z?
ABx'y`+ ABXY
АВ
ABx+ Bx'y`
ABx'y](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7d3e2a9d-ac86-4edb-bef9-bef68c8bc1cf%2Fdae5bd10-9745-4772-a762-c9e93fe2757f%2F9rura3_processed.jpeg&w=3840&q=75)
Transcribed Image Text:7
For the circuit above: B(t+1) equation can be
expressed as
B(t+1)= E(3,8,15)
Β (+1)-Σ(6,7,1 5)
B(t+1)= E(3,6,7)
B((+1)-Σ(6,7,8, 1 5)
B((+1)-Σ(7,8, 1 2)
8
For the circuit above. What is a Boolean
expression for z?
ABx'y`+ ABXY
АВ
ABx+ Bx'y`
ABx'y
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