For the chemical reaction Ca (s) + ½ O2 (g) → CaO (s) AH° = -635 kJ/mol. %3D What is the enthalpy for the reaction 2 CaO (s) → 2 Ca (s) + O2 (g)? kJ/mol 1 2 4 C 7 8 9. +/- х 100

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### Chemical Reaction and Enthalpy Calculation

For the chemical reaction:

\[ \text{Ca (s) + ½ O}_2 \text{ (g) } \rightarrow \text{CaO (s)} \]

the standard enthalpy change, \( \Delta H^\circ \), is \(-635 \text{ kJ/mol}\).

#### Question

What is the enthalpy for the reaction:

\[ \text{2 CaO (s)} \rightarrow \text{2 Ca (s) + O}_2 \text{ (g)}? \]

#### Explanation

**Reaction Analysis:**

- The given reaction is the formation of calcium oxide (CaO) from calcium (Ca) and oxygen (\(\text{O}_2\)).
- The enthalpy change of this formation reaction is exothermic with \(-635 \text{ kJ/mol}\).

**Calculating the Enthalpy for the Reverse Reaction:**

- The reaction we are asked to analyze is the reverse of the given formation reaction.
- For reversible reactions, the enthalpy change has the same magnitude but opposite sign.

**Result:**

For the reaction \( \text{2 CaO (s)} \rightarrow \text{2 Ca (s) + O}_2 \text{ (g)}\):

- The enthalpy change will be \( \Delta H = +635 \text{ kJ/mol} \times 2 = +1270 \text{ kJ/mol}\).

#### Diagram Description

The image includes a calculator-like interface for inputting numerical values. There are buttons labeled with numbers (0-9), a decimal point, a sign change button (\(+/-\)), a delete button (×), and a clear button (C). There is also a function for multiplying by 10. This section allows for the entering and manipulation of values for the calculation of enthalpy.
Transcribed Image Text:### Chemical Reaction and Enthalpy Calculation For the chemical reaction: \[ \text{Ca (s) + ½ O}_2 \text{ (g) } \rightarrow \text{CaO (s)} \] the standard enthalpy change, \( \Delta H^\circ \), is \(-635 \text{ kJ/mol}\). #### Question What is the enthalpy for the reaction: \[ \text{2 CaO (s)} \rightarrow \text{2 Ca (s) + O}_2 \text{ (g)}? \] #### Explanation **Reaction Analysis:** - The given reaction is the formation of calcium oxide (CaO) from calcium (Ca) and oxygen (\(\text{O}_2\)). - The enthalpy change of this formation reaction is exothermic with \(-635 \text{ kJ/mol}\). **Calculating the Enthalpy for the Reverse Reaction:** - The reaction we are asked to analyze is the reverse of the given formation reaction. - For reversible reactions, the enthalpy change has the same magnitude but opposite sign. **Result:** For the reaction \( \text{2 CaO (s)} \rightarrow \text{2 Ca (s) + O}_2 \text{ (g)}\): - The enthalpy change will be \( \Delta H = +635 \text{ kJ/mol} \times 2 = +1270 \text{ kJ/mol}\). #### Diagram Description The image includes a calculator-like interface for inputting numerical values. There are buttons labeled with numbers (0-9), a decimal point, a sign change button (\(+/-\)), a delete button (×), and a clear button (C). There is also a function for multiplying by 10. This section allows for the entering and manipulation of values for the calculation of enthalpy.
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