For the cell below, label the following on the diagram provided: Cu|0.10M Cu(NO3)2 || Ni|0.50M Ni(NO3)2 Observed EMF = 0.1V Anode Cathode Show solution in porous cup. Show solution in beaker. Show direction of electron flow in the wire Give reduction equation and voltage: Give oxidation equation and voltage: Give net equation and voltage: Identify anions: Identify cations:
For the cell below, label the following on the diagram provided: Cu|0.10M Cu(NO3)2 || Ni|0.50M Ni(NO3)2 Observed EMF = 0.1V Anode Cathode Show solution in porous cup. Show solution in beaker. Show direction of electron flow in the wire Give reduction equation and voltage: Give oxidation equation and voltage: Give net equation and voltage: Identify anions: Identify cations:
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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For the cell below, label the following on the diagram provided:
Cu|0.10M Cu(NO3)2 || Ni|0.50M Ni(NO3)2
Observed EMF = 0.1V
- Anode
- Cathode
- Show solution in porous cup.
- Show solution in beaker.
- Show direction of electron flow in the wire
- Give reduction equation and voltage:
- Give oxidation equation and voltage:
- Give net equation and voltage:
- Identify anions:
- Identify cations:
EXAMPLE ATTACHED.
![Electrolyti. Cell ( Non- Spontaneous)
Calculato the Average Curnont in Amps.
Amp= Coulomb/soc
f= 96,500 Coulommbs/mob
Data :
( P H=7
Final PH= 10.5
e
Time = 1omin
Vol KI solution 30.0ml
Hzot +Of
dathoda -GER
A node:LEo
Oven sll:
2I + 2H,0– I,+ Hz + OH"
Calcu lations:
-6
PoH - 3.5
[ONJ'= 3.16x10m
JOH
-6
9.5x1D mob e (96 500 Coul
mol
•92 caul.
bosm o boo Soc
99 Coulemb
boo see
.0015 Coul./soc
lomin
.3
|.5 xID A mps](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F22511752-e9ce-4588-8032-cd3bbfe8ca64%2F8ff16eb5-44ff-4d07-a3f7-10927e904ec6%2Fhe99anh_processed.png&w=3840&q=75)
Transcribed Image Text:Electrolyti. Cell ( Non- Spontaneous)
Calculato the Average Curnont in Amps.
Amp= Coulomb/soc
f= 96,500 Coulommbs/mob
Data :
( P H=7
Final PH= 10.5
e
Time = 1omin
Vol KI solution 30.0ml
Hzot +Of
dathoda -GER
A node:LEo
Oven sll:
2I + 2H,0– I,+ Hz + OH"
Calcu lations:
-6
PoH - 3.5
[ONJ'= 3.16x10m
JOH
-6
9.5x1D mob e (96 500 Coul
mol
•92 caul.
bosm o boo Soc
99 Coulemb
boo see
.0015 Coul./soc
lomin
.3
|.5 xID A mps
![voltmeter
angator
clips
volts](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F22511752-e9ce-4588-8032-cd3bbfe8ca64%2F8ff16eb5-44ff-4d07-a3f7-10927e904ec6%2Fj6214cn_processed.png&w=3840&q=75)
Transcribed Image Text:voltmeter
angator
clips
volts
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