For the binomial distribution P(x) = C7x(0.4)*(0.6)7-X, choose the correct histogram below and compute the mean andKstandard deviation for the distribution.Choose the correct histogram below.OA. P(x)0.50.30.2-0.1-0O C. P(x)0.50.440.30.240.140-B. P(x)0.5-0.4-0.3-0.2-0.1-0-D. P(x)0.5-The standard deviation of the binomial distribution is approximately0.4-0.3-0.2-0.1-0-The mean of the binomial distibution is (Type an integer or a decimal.)(Round to three decimal places.)23etleliew

Answered: Image /qna-images/answer/32e0c257-236b-45d8-8fa9-da3ce7d43176.jpg

Answered: For the binomial distribution P(x) =…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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You are conducting a study to see if the proportion of voters who prefer Candidate A is significantly more than 0.82. With H, : p > 0.82 you obtain a test statistic of z = 3.077. Use a normal distribution calculator and the test statistic to find the P-value accurate to 4 decimal places. It may be left-tailed, right-tailed, or 2-tailed. P-value =
K A process produces strings of Christmas tree lights that historically have experienced a defective rate of 6%. A customer has placed an order for 150 strings of lights. Use the normal approximation to the binomial distribution to answer parts a through e. a. Calculate the mean and standard deviation for this distribution. The mean is 9. (Round to four decimal places as needed.) The standard deviation is 2.9086. (Round to four decimal places as needed.) b. What is the probability that fewer than 4 strings in this order will be defective? The probability is 0.0292. (Round to four decimal places as needed.) c. What is the probability that exactly 10 strings in this order will be defective? The probability is (Round to four decimal places as needed.) View an example Get more help - H 1 |=| Vi 1. Clear all Check answer *
Here is a probability distribution: X 2 4 7 10 P(X) 0.3 0.05 0.3 0.35 Find the mean of this distribution. Enter your answer rounded to 2 decimal places. 6.40 Find the standard deviation of this distribution. Enter your answer rounded to 2 decimal places. 2.48 x
The round off errors when measuring the distance that a long jumper has jumped is uniformly distributed between 0 and 5.8 mm. Round values to 4 decimal places when possible. b. The standard deviation is c. The probability that the round a. The mean of this distribution is off error for a jumper's distance is exactly 0.3 is P(x-03)-d. The probability that the round off error for the distance that a long jumper has jumped is between 0 and 5 8 mm is PC1.7 x 5.2)- that the jump's round off error is greater than 1.76 is P(x > 1.76) Find the 81st percentile. e. The probability f P(x > 1.4 x > 0.6) h. Find the mnmum for the upper quartile.
The round off errors when measuring the distance that a long jumper has jumped is uniformly distributed between 0 and 4.7 mm. Round values to 4 decimal places when possible. The mean of this distribution is The standard deviation is The probability that the round off error for a jumper's distance is exactly 1.1 is P(x = 1.1) = The probability that the round off error for the distance that a long jumper has jumped is between 0 and 4.7 mm is P(0.2 < x < 0.9) = The probability that the jump's round off error is greater than 1.04 is P(x > 1.04) = P(x > 2.8 | x > 0.6) = Find the 81st percentile. Find the maximum for the lower quartile.
Find the probabilities for each, using the standard normal distribution. Shade the area of the region under the normal curve.
The round off errors when measuring the distance that a long jumper has jumped is uniformly distributed between 0 and 5.1 mm. Round values to 4 decimal places when possible. The mean of this distribution is . The standard deviation is . The probability that the round off error for a jumper's distance is exactly 4.3 is P(x=4.3)=P(x=4.3)= . The probability that the round off error for the distance that a long jumper has jumped is between 1.5 and 2.5 mm is P(1.5<x<2.5)=P(1.5<x<2.5)= . The probability that the jump's round off error is greater than 1.22 is P(x>1.22)=P(x>1.22)= . P(x>1.8∣x>0.5)=P(x>1.8∣x>0.5)= . Find the 54th percentile. Find the maximum for the lower quarter.
The time that it takes for the next train to come follows a Uniform distribution with f(x) =1/20 where x goes between 1 and 21 minutes. Round answers to 4 decimal places when possible. a. This is a Select an answer distribution. b. It is a Select an answer v distribution. c. The mean of this distribution is d. The standard deviation is e. Find the probability that the time will be at most 13 minutes. f. Find the probability that the time will be between 6 and 16 minutes. g. Find the 30th percentile. h. Find the probability that the time is more than 17 minutes given (or knowing that) it is at least 3 minutes.

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