For the below CB amplifier circuit: C5 10u R1 101k R2 11.2k 12 AIH 0 VCC ww Q1 www Figure 1. RC 12k Q2N3904 0 RE 1k C3 HH 16u Rsig www 50 O VBE=0.63V 0 B=100 Thermal Voltage VT=26mV, Vsig=10m V. C4 HH 10u Vin VOFF = 0 VAMPL 10m FREQ = 10k AC = V1 www Vout 2.6k Calculate the DC bias Analysis and using the values you found for the small signal parameters. Record the calculated input and output voltages in Table 3. Given that:
For the below CB amplifier circuit: C5 10u R1 101k R2 11.2k 12 AIH 0 VCC ww Q1 www Figure 1. RC 12k Q2N3904 0 RE 1k C3 HH 16u Rsig www 50 O VBE=0.63V 0 B=100 Thermal Voltage VT=26mV, Vsig=10m V. C4 HH 10u Vin VOFF = 0 VAMPL 10m FREQ = 10k AC = V1 www Vout 2.6k Calculate the DC bias Analysis and using the values you found for the small signal parameters. Record the calculated input and output voltages in Table 3. Given that:
Introductory Circuit Analysis (13th Edition)
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Solve 3
Transcribed Image Text:For the below CB amplifier circuit:
C5
10u
R1
101k
R2
11.2k
12
VBE=0.63V
AIHE
0
VCC
ww
Q1
www
Figure 1.
RC
12k
Q2N3904
0
RE
1k
C3
HI
16u
Rsig
0 B=100
Thermal Voltage VT=26mV, Vsig=10m V.
50
C4
HH
10u
Vin
VOFF = 0
VAMPL = 10m
FREQ = 10k
AC =
V1
Vout
Calculate the DC bias Analysis and using the values you found for the small signal
parameters. Record the calculated input and output voltages in Table 3.
Given that:
2.6k
![Value
1) Req
2) Veg
3) IB
4) IE
5) Ic
6) VCE
7) VE
8) VB
9) re
10) 9m
11) T
12) Zin
13) Zout
14) Vaut
15) Av
(₁ + 2/2)^-1
R2
R2
R1 + R2
(ß + 1) * IB
IB* B
-Veq+ Req*IB+ Vbe +Re [ (ß +1) *IB]=0
IE*RE
VBE+VE
* Vcc
-VCC+ VCE+RC (IC) +RE (IE) = 0
VT
IE
(IC)
(VT)
(B)
(9m)
Rin=
Vout
Vsig
(rn)
(B+1)
RC (RL)
Rout=
-B
(B+1) Rin+Rsig
Table 3
Equations
RC+(RL)
-Rin
(Vsig)
RC* (RL)
RC+(RL)
Final Value](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa7cf143d-c2c6-4213-971b-95909956e40e%2F44548189-0914-46d9-8215-1e080fafbedd%2Fhlj6l2_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Value
1) Req
2) Veg
3) IB
4) IE
5) Ic
6) VCE
7) VE
8) VB
9) re
10) 9m
11) T
12) Zin
13) Zout
14) Vaut
15) Av
(₁ + 2/2)^-1
R2
R2
R1 + R2
(ß + 1) * IB
IB* B
-Veq+ Req*IB+ Vbe +Re [ (ß +1) *IB]=0
IE*RE
VBE+VE
* Vcc
-VCC+ VCE+RC (IC) +RE (IE) = 0
VT
IE
(IC)
(VT)
(B)
(9m)
Rin=
Vout
Vsig
(rn)
(B+1)
RC (RL)
Rout=
-B
(B+1) Rin+Rsig
Table 3
Equations
RC+(RL)
-Rin
(Vsig)
RC* (RL)
RC+(RL)
Final Value
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