For the beam shown below: A. E B C D A 8 ft 6 ft 10 ft 8 ft + + + (a) Draw the influence lines for the reaction at C, the shear at D and the moment at E. A. B E D C 8 ft 6 ft 10 ft 8 ft + + I.L. for RC I.L. for V VD I.L. for ME (b) Suppose a uniformly distributed live load of 0.65 kip/ft and a concentrated live load of P-8 kip are applied to the beam. Use the results in part (a) to determine the maximum moment at E. Also show the position of the live load for this limiting case.

Could you explain in depth how you draw the influence lines for this problem using muller Breslau’s principle. The solution is given but I’m totally lost on how to draw the graph and were did the numbers on the graphs come from.

For a = 1.5m, determine the reactions at pin A and roller B. 1800 N/m A 4 m Solution: • There are two distributed loads acting on the beam, left and right. Replace them with equivalent concentrated loads respectively: 1. The distributed load on the left part of the beam is equivalent to F₁: o Magnitude of it: F₁ = N; o Location of it: x₁ = m to the right of A; 2. The distributed load on the right part of the beam is equivalent to F2: o Magnitude of it: F2 = N; o Location of it: X₂ = 600 N/m B 1. Reactions on A: 2 Reactions on R • The two supports are replaced by corresponding reactions: → m to the right of A;

Q2 Use the Müller-Breslau principle to sketch the influence lines for the vertical reaction at A, the shear at C, and the moment at C. D A C B E