For the beam (black line) and cable (green line) arrangement shown below, calculate the reactions at points A and B. a = 3.0 m, b = 1.5 m and c = 2.0 m. w = 4.5 kN/m and theta = 35 deg. Reaction force at A in y direction (kN, positive up): Reaction force at A in x direction (kN, positive right): Reaction force at B in y direction (kN, positive up): Reaction force at B in x direction (kN, positive right): RBX → Do ↑ RBY 0 RAX→ RAY b с W
For the beam (black line) and cable (green line) arrangement shown below, calculate the reactions at points A and B. a = 3.0 m, b = 1.5 m and c = 2.0 m. w = 4.5 kN/m and theta = 35 deg. Reaction force at A in y direction (kN, positive up): Reaction force at A in x direction (kN, positive right): Reaction force at B in y direction (kN, positive up): Reaction force at B in x direction (kN, positive right): RBX → Do ↑ RBY 0 RAX→ RAY b с W
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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![For the beam (black line) and cable (green line) arrangement shown below, calculate the reactions at points A and B. a = 3.0 m, b = 1.5 m and c = 2.0 m. w = 4.5 kN/m and theta = 35 deg.
Reaction force at A in y direction (kN, positive up):
Reaction force at A in x direction (kN, positive right):
Reaction force at B in y direction (kN, positive up):
Reaction force at B in x direction (kN, positive right):
RBX
↑
RBY
0
8
↑
RAY
RAX→
b
W](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F11518b29-f27e-4402-9bbf-a4835aa5d5a7%2F84414f14-dae0-472c-9165-b3a87397a3f4%2F7a274yj_processed.png&w=3840&q=75)
Transcribed Image Text:For the beam (black line) and cable (green line) arrangement shown below, calculate the reactions at points A and B. a = 3.0 m, b = 1.5 m and c = 2.0 m. w = 4.5 kN/m and theta = 35 deg.
Reaction force at A in y direction (kN, positive up):
Reaction force at A in x direction (kN, positive right):
Reaction force at B in y direction (kN, positive up):
Reaction force at B in x direction (kN, positive right):
RBX
↑
RBY
0
8
↑
RAY
RAX→
b
W
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