For the 6-carbon molecule below, how would you expect it to break into two pieces? a. two 3-carbon units b. one 2-carbon unit and one 4-carbon unit c. one 1-carbon unit, one 2-carbon unit, and one 3-carbon unit d. one 1-carbon unit and one 5-carbon unit
For the 6-carbon molecule below, how would you expect it to break into two pieces? a. two 3-carbon units b. one 2-carbon unit and one 4-carbon unit c. one 1-carbon unit, one 2-carbon unit, and one 3-carbon unit d. one 1-carbon unit and one 5-carbon unit
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ISBN:9781305957404
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For the 6-carbon molecule below, how would you expect it to break into two pieces?
a. two 3-carbon units
b. one 2-carbon unit and one 4-carbon unit
c. one 1-carbon unit, one 2-carbon unit, and one 3-carbon unit
d. one 1-carbon unit and one 5-carbon unit
I'm having a hard time identifying the correct location of Beta and Alpha. If the carbonyl beta is the second bond over from carbonyl, then the breakage would occur at bond C3-C4. This would then result in two 3-carbon units, right? The molecule in the image looks like fructose which would result in two 3-carbon units.
Transcribed Image Text:### Pentanal: Structural Formula
The image depicts the structural formula of Pentanal, an organic compound belonging to the aldehyde family.
#### Key Features:
- **Carbon Chain:** The compound features a straight carbon chain with five carbon atoms, characteristic of pentane derivatives.
- **Aldehyde Group:** At the end of the chain, a carbon atom is double-bonded to an oxygen atom, forming a carbonyl group (C=O), and is also bonded to a hydrogen atom, indicating the presence of an aldehyde functional group.
- **Oxygen Atom:** The oxygen atom in the carbonyl group is shown with lone electron pairs, represented by dots.
This structural representation is essential in understanding the chemical behavior and synthesis of aldehydes like Pentanal.
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