For the (4 x 4) pile group as shown in the figure, the settlement of pile group, in a normally consolidated clay stratum having properties as shown in the figure will be. (Load dispersion = 2 H:1 V) mm. 900 kN Normally consolidated clay Yt = 20 kN/m' 6 m w = 40% 8 m w, = 25% C, = 1.05 Hard stratum 250 mm Piles are spaced at 0.5 m c/c. Diameter of piles is 250 mm 0.5 m 0.5 m Top view

For the (4 x 4) pile group as shown in the figure, the settlement of pile group, in a normally consolidated clay stratum having properties as shown in the figure will be. (Load dispersion = 2 H:1 V) mm. 900 kN Normally consolidated clay Yt = 20 kN/m' 6 m w = 40% 8 m w, = 25% C, = 1.05 Hard stratum 250 mm Piles are spaced at 0.5 m c/c. Diameter of piles is 250 mm 0.5 m 0.5 m Top view

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Similar questions

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Consolidation of Settlemint
Example For the building shown in the figure below , the load was (ql=150 kN/m?), after 2.0 year the load becomes (q2=200 kN/m²) due to construction of new stories fined the total consolidation settlement under point A. 7 m 3.5 m Plan 7 m 3.5 m A 1 m Sand soil y-18.5 kN/m? , Yat. 20 kN/m WT ip-0.8 1m Profile 1 m Clay soil Y 21 kN/m? , Pc=80 kN/m? ,Cv=4 m?/year, Cc=0.4 , Ca= 0.015 , e=0.5 3 m
Do not round off answers in solving. Round off to two decimal place only to the final answer.
Consolidation.
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